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Find the inverse of each of the given functions.

[tex]\[
\begin{array}{l}
f(x) = 4x - 12 \\
f^{-1}(x) = \square x + \square
\end{array}
\][/tex]

[tex]\[ h(x) = \frac{2x - 4}{3} \][/tex]

[tex]\[ h^{-1}(x) = \frac{3x - 12}{2} \][/tex]


Sagot :

Let's find the inverse of the given function [tex]\( f(x) = 4x - 12 \)[/tex].

### Step-by-Step Solution

1. Write the function in terms of [tex]\( y \)[/tex]:
[tex]\[ y = 4x - 12 \][/tex]

2. Swap [tex]\( x \)[/tex] and [tex]\( y \)[/tex]. This represents the inverse relationship:
[tex]\[ x = 4y - 12 \][/tex]

3. Solve for [tex]\( y \)[/tex]:
[tex]\[ x + 12 = 4y \][/tex]
[tex]\[ y = \frac{x + 12}{4} \][/tex]

4. Rewrite the expression to identify the coefficients:
[tex]\[ y = \frac{1}{4}x + 3 \][/tex]

So, the inverse function [tex]\( f^{-1}(x) \)[/tex] is:
[tex]\[ f^{-1}(x) = \frac{1}{4}x + 3 \][/tex]

Thus, the coefficients for [tex]\( f^{-1}(x) \)[/tex] are:
[tex]\[ \begin{array}{l} f^{-1}(x) = 0.25x + 3.0 \end{array} \][/tex]

### Summary
The inverse function [tex]\( f^{-1}(x) \)[/tex] for the given function [tex]\( f(x) = 4x - 12 \)[/tex] is:
\[
f^{-1}(x) = 0.25x + 3.0 \