Get the answers you've been searching for with IDNLearn.com. Explore thousands of verified answers from experts and find the solutions you need, no matter the topic.
Sagot :
To find the simplest form of the given expression [tex]\((2x - 3)(3x^2 + 2x - 1)\)[/tex], we need to expand it by multiplying each term in the first polynomial by each term in the second polynomial and then combining like terms. Let's do this step by step.
Let’s expand [tex]\((2x - 3)(3x^2 + 2x - 1)\)[/tex]:
1. First, distribute [tex]\(2x\)[/tex]:
[tex]\(2x \cdot 3x^2 = 6x^3\)[/tex]
[tex]\(2x \cdot 2x = 4x^2\)[/tex]
[tex]\(2x \cdot (-1) = -2x\)[/tex]
2. Next, distribute [tex]\(-3\)[/tex]:
[tex]\(-3 \cdot 3x^2 = -9x^2\)[/tex]
[tex]\(-3 \cdot 2x = -6x\)[/tex]
[tex]\(-3 \cdot (-1) = 3\)[/tex]
Now, combine all the terms obtained from the distribution:
[tex]\[ 6x^3 + 4x^2 - 2x - 9x^2 - 6x + 3 \][/tex]
3. Combine like terms:
[tex]\[ 6x^3 + (4x^2 - 9x^2) + (-2x - 6x) + 3 \][/tex]
Simplify inside the parentheses:
[tex]\[ 6x^3 - 5x^2 - 8x + 3 \][/tex]
So the simplest form of the expression [tex]\((2x - 3)(3x^2 + 2x - 1)\)[/tex] is:
[tex]\[ 6x^3 - 5x^2 - 8x + 3 \][/tex]
Thus, the correct answer is:
[tex]\[ \boxed{C. \ 6x^3 - 5x^2 - 8x + 3} \][/tex]
Let’s expand [tex]\((2x - 3)(3x^2 + 2x - 1)\)[/tex]:
1. First, distribute [tex]\(2x\)[/tex]:
[tex]\(2x \cdot 3x^2 = 6x^3\)[/tex]
[tex]\(2x \cdot 2x = 4x^2\)[/tex]
[tex]\(2x \cdot (-1) = -2x\)[/tex]
2. Next, distribute [tex]\(-3\)[/tex]:
[tex]\(-3 \cdot 3x^2 = -9x^2\)[/tex]
[tex]\(-3 \cdot 2x = -6x\)[/tex]
[tex]\(-3 \cdot (-1) = 3\)[/tex]
Now, combine all the terms obtained from the distribution:
[tex]\[ 6x^3 + 4x^2 - 2x - 9x^2 - 6x + 3 \][/tex]
3. Combine like terms:
[tex]\[ 6x^3 + (4x^2 - 9x^2) + (-2x - 6x) + 3 \][/tex]
Simplify inside the parentheses:
[tex]\[ 6x^3 - 5x^2 - 8x + 3 \][/tex]
So the simplest form of the expression [tex]\((2x - 3)(3x^2 + 2x - 1)\)[/tex] is:
[tex]\[ 6x^3 - 5x^2 - 8x + 3 \][/tex]
Thus, the correct answer is:
[tex]\[ \boxed{C. \ 6x^3 - 5x^2 - 8x + 3} \][/tex]
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com has the answers you need. Thank you for visiting, and we look forward to helping you again soon.