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Answer:
To find the probability that a randomly selected salesperson has desk computers but not laptop computers, we can use the following information:
P(L): Probability of having a laptop computer = 0.42
P(D): Probability of having a desk computer = 0.65
P(L∩D): Probability of having both laptop and desk computers = 0.24
We need to find the probability that a salesperson has a desk computer but not a laptop computer. This can be represented as P(D∩¬L).
Using the principle of inclusion and exclusion in probability, we can find P(D∩¬L) as follows:
\[ P(D \cap \neg L) = P(D) - P(L \cap D) \]
Now we substitute the given probabilities:
\[ P(D \cap \neg L) = 0.65 - 0.24 \]
\[ P(D \cap \neg L) = 0.41 \]
Therefore, the probability that a randomly selected salesperson has desk computers but not laptop computers is 0.41 or 41%.
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