Answered

IDNLearn.com is committed to providing high-quality answers to your questions. Ask your questions and receive reliable, detailed answers from our dedicated community of experts.

An unbalanced chemical equation for the reaction of boron fluoride with lithium sulfite is shown below.

[tex] BF_3 + Li_2SO_3 \rightarrow B_2(SO_3)_3 + LiF [/tex]

What is the coefficient of lithium fluoride in the balanced chemical reaction?

A. 1
B. 3
C. 4
D. 6

Sagot :

GinnyAnsweridn
To determine the coefficient of lithium fluoride ([tex]\(LiF\)[/tex]) in the balanced chemical equation, we need to follow a systematic approach of balancing each element in the reaction.

The unbalanced equation is:
[tex]\[ BF_3 + Li_2SO_3 \rightarrow B_2(SO_3)_3 + LiF \][/tex]

We'll balance the elements one by one:

1. Balance Boron (B):
- On the left side, boron appears in [tex]\(BF_3\)[/tex].
- On the right side, boron appears in [tex]\(B_2(SO_3)_3\)[/tex].
- There are 2 boron atoms in [tex]\(B_2(SO_3)_3\)[/tex]. Therefore, we need 2 [tex]\(BF_3\)[/tex] molecules to balance boron.

[tex]\[ 2 BF_3 + Li_2SO_3 \rightarrow B_2(SO_3)_3 + LiF \][/tex]

2. Balance Fluorine (F):
- On the left side, fluorine appears in [tex]\(BF_3\)[/tex]. Each [tex]\(BF_3\)[/tex] molecule has 3 fluorine atoms.
- We have 2 [tex]\(BF_3\)[/tex] molecules, thus 2 x 3 = 6 fluorine atoms on the left side.
- On the right side, fluorine appears in [tex]\(LiF\)[/tex].
- To balance the 6 fluorine atoms, we need 6 [tex]\(LiF\)[/tex] molecules.

[tex]\[ 2 BF_3 + Li_2SO_3 \rightarrow B_2(SO_3)_3 + 6 LiF \][/tex]

3. Balance Lithium (Li):
- On the left side, lithium appears in [tex]\(Li_2SO_3\)[/tex].
- Each [tex]\(Li_2SO_3\)[/tex] molecule has 2 lithium atoms.
- On the right side, lithium appears in [tex]\(LiF\)[/tex].
- We need 6 lithium atoms to balance the equation, so we need 3 [tex]\(Li_2SO_3\)[/tex] molecules.

[tex]\[ 2 BF_3 + 3 Li_2SO_3 \rightarrow B_2(SO_3)_3 + 6 LiF \][/tex]

4. Balance Sulfur (S) and Oxygen (O):
- Let's double-check the sulfur and oxygen balance.
- On the left side, sulfur appears in [tex]\(Li_2SO_3\)[/tex] and we have 3 [tex]\(Li_2SO_3\)[/tex] molecules. Thus, there are [tex]\(3 \times 1 = 3\)[/tex] sulfur atoms and [tex]\(3 \times 3 = 9\)[/tex] oxygen atoms.
- On the right side, sulfur appears in [tex]\(B_2(SO_3)_3\)[/tex]. Each [tex]\(B_2(SO_3)_3\)[/tex] molecule has 3 sulfur atoms and [tex]\(3 \times 3 = 9\)[/tex] oxygen atoms.
- Both sulfur and oxygen are balanced.

The balanced chemical equation is:
[tex]\[ 2 BF_3 + 3 Li_2SO_3 \rightarrow B_2(SO_3)_3 + 6 LiF \][/tex]

Thus, the coefficient of lithium fluoride ([tex]\(LiF\)[/tex]) in the balanced chemical reaction is [tex]\( \boxed{6} \)[/tex].
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.