IDNLearn.com: Where your questions meet expert answers and community support. Ask anything and receive prompt, well-informed answers from our community of experienced experts.
Sagot :
To solve the expression [tex]\(0.54 \times 0.54 - 0.46 \times 0.46\)[/tex] using identities, we can use the difference of squares identity. The difference of squares identity states that:
[tex]\[ a^2 - b^2 = (a - b)(a + b) \][/tex]
Here, we have:
- [tex]\(a = 0.54\)[/tex]
- [tex]\(b = 0.46\)[/tex]
Step-by-step solution:
1. Identify the terms: Let [tex]\(a = 0.54\)[/tex] and [tex]\(b = 0.46\)[/tex].
2. Calculate [tex]\(a + b\)[/tex]:
[tex]\[ a + b = 0.54 + 0.46 = 1.0 \][/tex]
3. Calculate [tex]\(a - b\)[/tex]:
[tex]\[ a - b = 0.54 - 0.46 = 0.08 \][/tex]
4. Apply the difference of squares identity:
[tex]\[ a^2 - b^2 = (a - b)(a + b) \][/tex]
5. Substitute the calculated values:
[tex]\[ 0.54^2 - 0.46^2 = (0.08)(1.0) \][/tex]
6. Calculate the final result:
[tex]\[ 0.08 \times 1.0 = 0.08000000000000002 \][/tex]
Therefore, the value of [tex]\(0.54 \times 0.54 - 0.46 \times 0.46\)[/tex] is [tex]\(0.08000000000000002\)[/tex].
[tex]\[ a^2 - b^2 = (a - b)(a + b) \][/tex]
Here, we have:
- [tex]\(a = 0.54\)[/tex]
- [tex]\(b = 0.46\)[/tex]
Step-by-step solution:
1. Identify the terms: Let [tex]\(a = 0.54\)[/tex] and [tex]\(b = 0.46\)[/tex].
2. Calculate [tex]\(a + b\)[/tex]:
[tex]\[ a + b = 0.54 + 0.46 = 1.0 \][/tex]
3. Calculate [tex]\(a - b\)[/tex]:
[tex]\[ a - b = 0.54 - 0.46 = 0.08 \][/tex]
4. Apply the difference of squares identity:
[tex]\[ a^2 - b^2 = (a - b)(a + b) \][/tex]
5. Substitute the calculated values:
[tex]\[ 0.54^2 - 0.46^2 = (0.08)(1.0) \][/tex]
6. Calculate the final result:
[tex]\[ 0.08 \times 1.0 = 0.08000000000000002 \][/tex]
Therefore, the value of [tex]\(0.54 \times 0.54 - 0.46 \times 0.46\)[/tex] is [tex]\(0.08000000000000002\)[/tex].
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Your questions find clarity at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.