IDNLearn.com makes it easy to find accurate answers to your specific questions. Find the solutions you need quickly and accurately with help from our knowledgeable community.
Sagot :
To find the acceleration of the wooden block when it hits the sensor, we can use Newton's second law of motion, which states that force ([tex]\( F \)[/tex]) equals mass ([tex]\( m \)[/tex]) multiplied by acceleration ([tex]\( a \)[/tex]). This can be written as:
[tex]\[ F = m \cdot a \][/tex]
Given the values:
- The mass ([tex]\( m \)[/tex]) of the wooden block is 0.5 kilograms.
- The force ([tex]\( F \)[/tex]) measured by the sensor is 4.9 newtons.
We need to solve for the acceleration ([tex]\( a \)[/tex]). We can rearrange the equation to solve for [tex]\( a \)[/tex]:
[tex]\[ a = \frac{F}{m} \][/tex]
Substituting in the known values:
[tex]\[ a = \frac{4.9 \, \text{newtons}}{0.5 \, \text{kilograms}} \][/tex]
When we perform the division:
[tex]\[ a = 9.8 \, \text{m/s}^2 \][/tex]
Therefore, the acceleration of the wooden block when it hits the sensor is [tex]\( 9.8 \, \text{m/s}^2 \)[/tex].
The correct answer is:
D. [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]
[tex]\[ F = m \cdot a \][/tex]
Given the values:
- The mass ([tex]\( m \)[/tex]) of the wooden block is 0.5 kilograms.
- The force ([tex]\( F \)[/tex]) measured by the sensor is 4.9 newtons.
We need to solve for the acceleration ([tex]\( a \)[/tex]). We can rearrange the equation to solve for [tex]\( a \)[/tex]:
[tex]\[ a = \frac{F}{m} \][/tex]
Substituting in the known values:
[tex]\[ a = \frac{4.9 \, \text{newtons}}{0.5 \, \text{kilograms}} \][/tex]
When we perform the division:
[tex]\[ a = 9.8 \, \text{m/s}^2 \][/tex]
Therefore, the acceleration of the wooden block when it hits the sensor is [tex]\( 9.8 \, \text{m/s}^2 \)[/tex].
The correct answer is:
D. [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Trust IDNLearn.com for all your queries. We appreciate your visit and hope to assist you again soon.