IDNLearn.com provides a seamless experience for finding the answers you need. Join our community to access reliable and comprehensive responses to your questions from experienced professionals.

What is the multiplicative rate of change of the function represented in the table?

\begin{tabular}{|c|c|}
\hline [tex]$x$[/tex] & [tex]$y$[/tex] \\
\hline 1 & 0.25 \\
\hline 2 & 0.125 \\
\hline 3 & 0.0625 \\
\hline 4 & 0.03125 \\
\hline
\end{tabular}

A. 0.2
B. 0.25
C. 0.5
D. 0.75


Sagot :

To determine the multiplicative rate of change of the given exponential function, we need to examine how the [tex]\( y \)[/tex]-values change as the [tex]\( x \)[/tex]-values increase. The given [tex]\( x \)[/tex]-values are 1, 2, 3, and 4, with corresponding [tex]\( y \)[/tex]-values of 0.25, 0.125, 0.0625, and 0.03125.

An exponential function has a consistent multiplicative rate of change, meaning that the ratio between successive [tex]\( y \)[/tex]-values remains constant.

Let's find the ratios between successive [tex]\( y \)[/tex]-values:

1. The ratio between the [tex]\( y \)[/tex]-value for [tex]\( x = 2 \)[/tex] and the [tex]\( y \)[/tex]-value for [tex]\( x = 1 \)[/tex]:
[tex]\[ \text{Rate of change}_1 = \frac{y (2)}{y (1)} = \frac{0.125}{0.25} = 0.5 \][/tex]

2. The ratio between the [tex]\( y \)[/tex]-value for [tex]\( x = 3 \)[/tex] and the [tex]\( y \)[/tex]-value for [tex]\( x = 2 \)[/tex]:
[tex]\[ \text{Rate of change}_2 = \frac{y (3)}{y (2)} = \frac{0.0625}{0.125} = 0.5 \][/tex]

3. The ratio between the [tex]\( y \)[/tex]-value for [tex]\( x = 4 \)[/tex] and the [tex]\( y \)[/tex]-value for [tex]\( x = 3 \)[/tex]:
[tex]\[ \text{Rate of change}_3 = \frac{y (4)}{y (3)} = \frac{0.03125}{0.0625} = 0.5 \][/tex]

Since the ratio remains consistent at 0.5 for each comparison, the multiplicative rate of change of the function is:

[tex]\[ \boxed{0.5} \][/tex]