Join IDNLearn.com and become part of a knowledge-sharing community that thrives on curiosity. Our platform provides trustworthy answers to help you make informed decisions quickly and easily.
Sagot :
To determine which function includes [tex]\(-4\)[/tex] in its range, we need to analyze each of the given functions one by one.
### Function 1: [tex]\( y = \sqrt{x} - 5 \)[/tex]
Let's set the function equal to [tex]\(-4\)[/tex]:
[tex]\[ \sqrt{x} - 5 = -4 \][/tex]
Add 5 to both sides:
[tex]\[ \sqrt{x} = 1 \][/tex]
Square both sides to remove the square root:
[tex]\[ x = 1 \][/tex]
Since [tex]\(x = 1\)[/tex] is a non-negative number, it is a valid solution. Therefore, [tex]\(-4\)[/tex] is included in the range of [tex]\( y = \sqrt{x} - 5 \)[/tex].
### Function 2: [tex]\( y = \sqrt{x} + 5 \)[/tex]
Set the function equal to [tex]\(-4\)[/tex]:
[tex]\[ \sqrt{x} + 5 = -4 \][/tex]
Subtract 5 from both sides:
[tex]\[ \sqrt{x} = -9 \][/tex]
Since the square root of a non-negative number cannot be negative, this equation has no real solutions. Therefore, [tex]\(-4\)[/tex] is not included in the range of [tex]\( y = \sqrt{x} + 5 \)[/tex].
### Function 3: [tex]\( y = \sqrt{x+5} \)[/tex]
Set the function equal to [tex]\(-4\)[/tex]:
[tex]\[ \sqrt{x+5} = -4 \][/tex]
The square root of a non-negative number cannot be negative. Therefore, this equation has no real solutions, and [tex]\(-4\)[/tex] is not included in the range of [tex]\( y = \sqrt{x+5} \)[/tex].
### Function 4: [tex]\( y = \sqrt{x-5} \)[/tex]
Set the function equal to [tex]\(-4\)[/tex]:
[tex]\[ \sqrt{x-5} = -4 \][/tex]
Similarly, the square root of a non-negative number cannot be negative. Therefore, this equation has no real solutions, and [tex]\(-4\)[/tex] is not included in the range of [tex]\( y = \sqrt{x-5} \)[/tex].
### Conclusion:
The only function whose range includes [tex]\(-4\)[/tex] is:
[tex]\[ y = \sqrt{x} - 5 \][/tex]
### Function 1: [tex]\( y = \sqrt{x} - 5 \)[/tex]
Let's set the function equal to [tex]\(-4\)[/tex]:
[tex]\[ \sqrt{x} - 5 = -4 \][/tex]
Add 5 to both sides:
[tex]\[ \sqrt{x} = 1 \][/tex]
Square both sides to remove the square root:
[tex]\[ x = 1 \][/tex]
Since [tex]\(x = 1\)[/tex] is a non-negative number, it is a valid solution. Therefore, [tex]\(-4\)[/tex] is included in the range of [tex]\( y = \sqrt{x} - 5 \)[/tex].
### Function 2: [tex]\( y = \sqrt{x} + 5 \)[/tex]
Set the function equal to [tex]\(-4\)[/tex]:
[tex]\[ \sqrt{x} + 5 = -4 \][/tex]
Subtract 5 from both sides:
[tex]\[ \sqrt{x} = -9 \][/tex]
Since the square root of a non-negative number cannot be negative, this equation has no real solutions. Therefore, [tex]\(-4\)[/tex] is not included in the range of [tex]\( y = \sqrt{x} + 5 \)[/tex].
### Function 3: [tex]\( y = \sqrt{x+5} \)[/tex]
Set the function equal to [tex]\(-4\)[/tex]:
[tex]\[ \sqrt{x+5} = -4 \][/tex]
The square root of a non-negative number cannot be negative. Therefore, this equation has no real solutions, and [tex]\(-4\)[/tex] is not included in the range of [tex]\( y = \sqrt{x+5} \)[/tex].
### Function 4: [tex]\( y = \sqrt{x-5} \)[/tex]
Set the function equal to [tex]\(-4\)[/tex]:
[tex]\[ \sqrt{x-5} = -4 \][/tex]
Similarly, the square root of a non-negative number cannot be negative. Therefore, this equation has no real solutions, and [tex]\(-4\)[/tex] is not included in the range of [tex]\( y = \sqrt{x-5} \)[/tex].
### Conclusion:
The only function whose range includes [tex]\(-4\)[/tex] is:
[tex]\[ y = \sqrt{x} - 5 \][/tex]
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. IDNLearn.com has the answers you need. Thank you for visiting, and we look forward to helping you again soon.