Let's address the question step-by-step.
Given the table:
| Outcome | Number of Throws |
|---------|------------------|
| 1 | 9 |
| 2 | 11 |
| 3 | 10 |
| 4 | 8 |
| 5 | 5 |
| 6 | |
The notion of rolling a 27 is not a standard die outcome, so we assume it's an impossibility.
1. Step 1: Determine the total number of trials.
By adding all the given numbers of throws, we get:
[tex]\[
9 + 11 + 10 + 8 + 5 = 43
\][/tex]
2. Step 2: Identify the number of trials where the outcome is 27.
Since the outcome 27 doesn't exist in typical die rolls (or isn't part of the given table), the number of trials where 27 occurs is 0.
3. Step 3: Calculate the experimental probability of rolling a 27.
The formula for experimental probability is given by:
[tex]\[
\text{Experimental Probability} = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Trials}}
\][/tex]
For rolling a 27, the number of favorable outcomes is 0, and the total number of trials is 43. Hence:
[tex]\[
\text{Experimental Probability of 27} = \frac{0}{43} = 0.0
\][/tex]
So, the total number of trials is 43, the number of trials with a 27 outcome is 0, and the experimental probability of rolling a 27 is 0.0.
