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Sagot :
Answers: [tex]x = 2+\sqrt{7} \ \text{ or } \ x = 2-\sqrt{7}[/tex]
Work Shown
a = 1, b = -4, c = -3
[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-4)\pm\sqrt{(-4)^2-4(1)(-3)}}{2(1)}\\\\x = \frac{4\pm\sqrt{16 + 12}}{2}\\\\x = \frac{4\pm\sqrt{28}}{2}\\\\x = \frac{4\pm\sqrt{4*7}}{2}\\\\[/tex]
[tex]x = \frac{4\pm\sqrt{4}*\sqrt{7}}{2}\\\\x = \frac{4\pm2\sqrt{7}}{2}\\\\x = \frac{2(2\pm\sqrt{7})}{2}\\\\x = 2\pm\sqrt{7}\\\\x = 2+\sqrt{7} \ \text{ or } \ x = 2-\sqrt{7}\\\\x \approx 4.6457513 \ \text{ or } \ x \approx -0.6457513\\\\[/tex]
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