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Which is the simplified form of [tex][tex]$r^{-7} + s^{-12}$[/tex][/tex]?

A. [tex]\frac{1}{r^7 s^{12}}[/tex]
B. [tex]-r^7 - s^{12}[/tex]
C. [tex]\frac{r^7}{s^{12}}[/tex]
D. [tex]\frac{1}{r^7} + \frac{1}{s^{12}}[/tex]


Sagot :

To simplify the expression [tex]\( r^{-7} + s^{-12} \)[/tex]:

1. Understand negative exponents:
- A negative exponent indicates the reciprocal of the base raised to the corresponding positive exponent.
- Thus, [tex]\( r^{-7} \)[/tex] can be rewritten as [tex]\( \frac{1}{r^7} \)[/tex].
- Similarly, [tex]\( s^{-12} \)[/tex] can be rewritten as [tex]\( \frac{1}{s^{12}} \)[/tex].

2. Rewrite the terms using positive exponents:
- [tex]\( r^{-7} = \frac{1}{r^7} \)[/tex]
- [tex]\( s^{-12} = \frac{1}{s^{12}} \)[/tex]

3. Combine the simplified terms:
- Add the two terms together to get [tex]\( \frac{1}{r^7} + \frac{1}{s^{12}} \)[/tex].

Thus, the simplified form of [tex]\( r^{-7} + s^{-12} \)[/tex] is:

[tex]\[ \frac{1}{r^7} + \frac{1}{s^{12}} \][/tex]

Therefore, the correct answer is:

[tex]\[ \boxed{\frac{1}{r^7} + \frac{1}{s^{12}}} \][/tex]