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Problem 6: (11% of Assignment Value)

Suppose the starter motor of a large truck draws [tex][tex]$265 A$[/tex][/tex] of current from a [tex][tex]$22 V$[/tex][/tex] battery hookup.

Randomized Variables:
[tex]\[
\begin{array}{l}
I = 265 \, \text{A} \\
\Delta V = 22 \, \text{V}
\end{array}
\][/tex]

Sagot :

GinnyAnsweridn
To determine the power consumed by the starter motor of a large truck, we need to use the formula for electrical power. The formula for power in an electric circuit is given by:

[tex]\[ P = I \times V \][/tex]

where:
- [tex]\( P \)[/tex] is the power in watts (W)
- [tex]\( I \)[/tex] is the current in amperes (A)
- [tex]\( V \)[/tex] is the voltage in volts (V)

Given the following values:
- Current, [tex]\( I = 265 \, A \)[/tex]
- Voltage, [tex]\( V = 22 \, V \)[/tex]

we can plug these values into the formula to determine the power.

Step-by-step solution:
1. Identify the given values:
[tex]\[ I = 265 \, A \][/tex]
[tex]\[ V = 22 \, V \][/tex]

2. Substitute the given values into the power formula:
[tex]\[ P = 265 \, A \times 22 \, V \][/tex]

3. Calculate the power:
[tex]\[ P = 5830 \, W \][/tex]

Therefore, the power consumed by the starter motor is:

[tex]\[ \boxed{5830 \, W} \][/tex]
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