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A circuit with a resistance of [tex][tex]$R = 79 \Omega$[/tex][/tex] is connected to a battery with a potential difference across the terminals of [tex][tex]$\Delta V = 5.5 V$[/tex][/tex].

Part (a)
Input an expression for the current passing through the circuit, [tex]I[/tex].

Sagot :

GinnyAnsweridn
Certainly! Let's walk through the solution step by step.

To find the current [tex]\( I \)[/tex] passing through a circuit, we can use Ohm's Law, which states that the current [tex]\( I \)[/tex] is equal to the potential difference [tex]\( V \)[/tex] divided by the resistance [tex]\( R \)[/tex]. The formula for Ohm's Law is:

[tex]\[ I = \frac{V}{R} \][/tex]

We are given:

- The resistance [tex]\( R = 79 \, \Omega \)[/tex]
- The potential difference [tex]\( V = 5.5 \, V \)[/tex]

Substituting these values into Ohm's Law, we get:

[tex]\[ I = \frac{5.5 \, V}{79 \, \Omega} \][/tex]

Simplifying this expression, we obtain:

[tex]\[ I \approx 0.0696 \, A \][/tex]

Therefore, the current passing through the circuit is approximately [tex]\( 0.0696 \, A \)[/tex], or 69.6 milliamps (mA).
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