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Which quadratic equation would be used to solve for the unknown dimensions?

A. [tex]0 = 2w^2[/tex]

B. [tex]512 = w^2[/tex]

C. [tex]512 = 2w^2[/tex]

D. [tex]512 = 2l + 2w[/tex]


Sagot :

To solve for the unknown dimensions, we need to identify the correct quadratic equation from the given choices.

The choices provided are:
1. [tex]\( 0 = 2w^2 \)[/tex]
2. [tex]\( 512 = w^2 \)[/tex]
3. [tex]\( 512 = 2w^2 \)[/tex]
4. [tex]\( 512 = 2l + 2w \)[/tex]

Let's analyze them step by step:

1. The equation [tex]\( 0 = 2w^2 \)[/tex] suggests that multiplying 2 by [tex]\( w^2 \)[/tex] results in 0, which implies [tex]\( w \)[/tex] would be 0. Since we are solving for an unknown dimension that results in a specific value (512 in this case), this equation does not suit our requirement.

2. The equation [tex]\( 512 = w^2 \)[/tex] implies that [tex]\( w^2 \)[/tex] equals 512 directly without any consideration of other coefficients or variables. This doesn't fit our scenario where the equation involves a coefficient alongside [tex]\( w^2 \)[/tex].

3. The equation [tex]\( 512 = 2w^2 \)[/tex] appears to be the accurate quadratic equation because it suggests that 512 is twice the value of [tex]\( w^2 \)[/tex]. This fits the requirement as it specifically uses [tex]\( w^2 \)[/tex] multiplied by a coefficient to equal 512.

4. The equation [tex]\( 512 = 2l + 2w \)[/tex] is a linear equation and does not involve a squared term. Hence, it does not represent a quadratic equation suitable for solving for dimensions in this context.

After analyzing each option, the correct quadratic equation to solve for the unknown dimensions is:
[tex]\[ 512 = 2w^2 \][/tex]