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A transverse traveling wave on a cord is represented by D=0.61sin(4.2x+47t) where D and x are in meters and t is in seconds. Determine the amplitude of this wave

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Answer:

0.61

Explanation:

The general equation of a progressive wave:

y = A sin (wt ± kx) where A is the amplitude, w = angular frequency and k = phase number.

Therefore, a transverse travelling wave represented by D = 0.61 sin (4.2x + 47t),

the amplitude of this wave is 0.61

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