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If the mass of an object is 3 kg, the gravitational field strength is 9.8 N/kg, and the change in height is 3 m, what is the change in gravitational potential energy stored?

Sagot :

GinnyAnsweridn
Sure, let's solve this step-by-step.

We need to find the change in gravitational potential energy stored.

The formula for gravitational potential energy (ΔE_p) is:
[tex]\[ \Delta E_p = m \cdot g \cdot \Delta h \][/tex]
where:
- \( m \) is the mass of the object in kilograms
- \( g \) is the gravitational field strength in newtons per kilogram (N/kg)
- \( \Delta h \) is the change in height in meters

Given:
- The mass, \( m \), is 3 kg
- The gravitational field strength, \( g \), is 9.8 N/kg
- The change in height, \( \Delta h \), is 3 meters

Now substitute these values into the formula:

[tex]\[ \Delta E_p = 3 \, \text{kg} \cdot 9.8 \, \text{N/kg} \cdot 3 \, \text{m} \][/tex]

Perform the multiplication:

[tex]\[ \Delta E_p = 3 \cdot 9.8 \cdot 3 \][/tex]
[tex]\[ \Delta E_p = 88.2 \][/tex]

Thus, the change in gravitational potential energy stored is 88.2 joules (J).
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