Discover a wealth of knowledge and get your questions answered on IDNLearn.com. Find reliable solutions to your questions quickly and accurately with help from our dedicated community of experts.
Sagot :
To find the hydronium ion concentration \([H_3O^+]\) of a solution with a given \( \text{pOH} \) of 6.90, we follow these steps:
1. Calculate the pH:
The relationship between pH and pOH is given by:
[tex]\[ \text{pH} + \text{pOH} = 14 \][/tex]
So, we can find the pH by subtracting the pOH from 14:
[tex]\[ \text{pH} = 14 - \text{pOH} = 14 - 6.90 = 7.10 \][/tex]
2. Calculate the hydronium ion concentration \([H_3O^+]\):
The hydronium ion concentration can be found using the formula:
[tex]\[ [H_3O^+] = 10^{-\text{pH}} \][/tex]
Plugging in the pH value:
[tex]\[ [H_3O^+] = 10^{-7.10} \approx 7.94 \times 10^{-8} \, M \][/tex]
3. Compare calculated \([H_3O^+]\) with given choices:
We are given the following options:
[tex]\[ \begin{align*} &6.29 \times 10^{-7} \, M \\ &6.53 \times 10^{-7} \, M \\ &7.18 \times 10^{-8} \, M \\ &7.94 \times 10^{-8} \, M \\ \end{align*} \][/tex]
The calculated \( [H_3O^+] \) value is \( \approx 7.94 \times 10^{-8} \, M \), which matches most closely with the option \( 7.94 \times 10^{-8} \, M \).
Therefore, the hydronium ion concentration is [tex]\( 7.94 \times 10^{-8} \, M \)[/tex], which matches the fourth option.
1. Calculate the pH:
The relationship between pH and pOH is given by:
[tex]\[ \text{pH} + \text{pOH} = 14 \][/tex]
So, we can find the pH by subtracting the pOH from 14:
[tex]\[ \text{pH} = 14 - \text{pOH} = 14 - 6.90 = 7.10 \][/tex]
2. Calculate the hydronium ion concentration \([H_3O^+]\):
The hydronium ion concentration can be found using the formula:
[tex]\[ [H_3O^+] = 10^{-\text{pH}} \][/tex]
Plugging in the pH value:
[tex]\[ [H_3O^+] = 10^{-7.10} \approx 7.94 \times 10^{-8} \, M \][/tex]
3. Compare calculated \([H_3O^+]\) with given choices:
We are given the following options:
[tex]\[ \begin{align*} &6.29 \times 10^{-7} \, M \\ &6.53 \times 10^{-7} \, M \\ &7.18 \times 10^{-8} \, M \\ &7.94 \times 10^{-8} \, M \\ \end{align*} \][/tex]
The calculated \( [H_3O^+] \) value is \( \approx 7.94 \times 10^{-8} \, M \), which matches most closely with the option \( 7.94 \times 10^{-8} \, M \).
Therefore, the hydronium ion concentration is [tex]\( 7.94 \times 10^{-8} \, M \)[/tex], which matches the fourth option.
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for answers ends at IDNLearn.com. Thank you for visiting, and we hope to assist you again soon.