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A rectangle has a length that is 5 centimeters longer than its width. The perimeter of the rectangle is 30 centimeters. Find the dimensions of the width and length of this rectangle.

Sagot :

Answer:width:5 centimeters

Length:10 centimeters

Explanation:To find the dimensions of the rectangle, let's denote the width of the rectangle as \( w \) centimeters. Given that the length is 5 centimeters longer than the width, the length can be represented as \( w + 5 \) centimeters.

The formula for the perimeter of a rectangle is given by:

\[ P = 2(\text{length} + \text{width}) \]

Substituting the given perimeter (30 centimeters) and the expressions for length and width, we get:

\[ 30 = 2(w + (w + 5)) \]

Simplifying the equation:

\[ 30 = 2(2w + 5) \]

\[ 30 = 4w + 10 \]

Subtract 10 from both sides:

\[ 20 = 4w \]

Divide both sides by 4:

\[ w = 5 \]

Now, we find the length by adding 5 centimeters to the width:

\[ \text{Length} = w + 5 = 5 + 5 = 10 \]

Therefore, the dimensions of the rectangle are:

- Width: 5 centimeters

- Length: 10 centimeters

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