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Complete the following cumulative frequency table.
[tex]\[
\begin{tabular}{|c|c|c|}
\hline
Class mark & Frequency & Less than type Frequency \\
\hline
[tex]$0-10$[/tex] & 3 & 3 \\ [tex]$10-20$[/tex] & 15 & [tex]$3+15=\square$[/tex] \\ [tex]$20-30$[/tex] & 20 & [tex]$18+20=38$[/tex] \\ [tex]$30-40$[/tex] & 12 & [tex]$38+12=50$[/tex] \\ \hline Total & [tex]$N=\square 0$[/tex] & \\ \hline \end{tabular} \][/tex]
Sure! Let's complete the cumulative frequency table step by step.
We'll start with the given data and fill in the missing parts:
1. For the class mark "0-10": - Frequency: 3 - Less than type Frequency: 3 (This is directly given)
2. For the class mark "10-20": - Frequency: 15 - Less than type Frequency: We know the previous cumulative frequency is 3. [tex]\[
\text{Cumulative Frequency} = 3 + 15 = 18
\][/tex] So, the less than type Frequency is 18.
3. For the class mark "20-30": - Frequency: 20 - Less than type Frequency: We know the previous cumulative frequency is 18. [tex]\[
\text{Cumulative Frequency} = 18 + 20 = 38
\][/tex] So, the less than type Frequency is 38.
4. For the class mark "30-40": - Frequency: 12 - Less than type Frequency: We know the previous cumulative frequency is 38. [tex]\[
\text{Cumulative Frequency} = 38 + 12 = 50
\][/tex] So, the less than type Frequency is 50.
Finally, we sum up all the frequencies to get the total frequency \( N \): [tex]\[
N = 3 + 15 + 20 + 12 = 50
\][/tex]
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