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Sagot :
To find out how much longer Emma can run and still beat her previous time of 1 hour and 10 minutes (which is equivalent to 70 minutes), let's break down the problem step by step.
1. Identify the previous time:
Emma's previous 10-kilometer time is \(70\) minutes.
2. Determine current running time:
Emma has already run for \(55\) minutes.
3. Set up the inequality:
We need to find out how much more time she can run, let's call this additional time \(t\). To beat her previous time, the total running time should be less than \(70\) minutes.
The total running time is the sum of the time she has already run and the additional time she will run:
\( t + 55 \)
To beat her previous time of \(70\) minutes, we set up the inequality:
[tex]\[ t + 55 < 70 \][/tex]
When rearranging this inequality, we can also write it as:
[tex]\[ 70 > t + 55 \][/tex]
Thus, the inequality \(70 > t + 55\) can be used to find how much longer Emma can run and still beat her previous time.
The correct choice is:
[tex]\[ 70 > t + 55 \][/tex]
1. Identify the previous time:
Emma's previous 10-kilometer time is \(70\) minutes.
2. Determine current running time:
Emma has already run for \(55\) minutes.
3. Set up the inequality:
We need to find out how much more time she can run, let's call this additional time \(t\). To beat her previous time, the total running time should be less than \(70\) minutes.
The total running time is the sum of the time she has already run and the additional time she will run:
\( t + 55 \)
To beat her previous time of \(70\) minutes, we set up the inequality:
[tex]\[ t + 55 < 70 \][/tex]
When rearranging this inequality, we can also write it as:
[tex]\[ 70 > t + 55 \][/tex]
Thus, the inequality \(70 > t + 55\) can be used to find how much longer Emma can run and still beat her previous time.
The correct choice is:
[tex]\[ 70 > t + 55 \][/tex]
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