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Which of the following equations is not a linear equation?

A) [tex]\frac{1}{2}x + 3y = 2[/tex]
B) [tex]x^3 - 5y^2 = 4[/tex]
C) [tex]x = 2[/tex]
D) [tex]y = 4[/tex]


Sagot :

To determine which of the given equations is not a linear equation, we need to check if each equation can be written in the standard form of a linear equation. A linear equation involves variables (like \( x \) and \( y \)) raised only to the first power and does not include products of these variables or any non-linear functions like \(\sin(x)\) or \(\exp(y)\).

Let's examine each equation:

### Equation A: \(\frac{1}{2} x + 3 y = 2\)
Here, \(\frac{1}{2} x\) and \(3 y\) are both linear terms because each variable is raised to the power of 1. This is a standard form linear equation.

### Equation B: \(x^3 - 5 y^2 = 4\)
In this equation, \(x\) is raised to the power of 3 and \(y\) is raised to the power of 2. Both of these terms are non-linear because the variables \(x\) and \(y\) are not raised solely to the first power.

### Equation C: \(x = 2\)
This represents a vertical line, which is indeed a linear equation because it can be viewed as \(1 \cdot x + 0 \cdot y = 2\).

### Equation D: \(y = 4\)
Similarly, this represents a horizontal line, which is also a linear equation because it can be seen as \(0 \cdot x + 1 \cdot y = 4\).

From this analysis, we can clearly see that the equation which is not a linear equation is:

[tex]\[ B) x^3 - 5 y^2 = 4 \][/tex]

So, the answer is B.