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A fair six-sided die is thrown once. Select the probability of a 3 showing on the die.

[tex]\[
\begin{array}{ccccc}
\frac{1}{6} & \frac{1}{2} & 6\% & \frac{1}{3} & 1:7 \\
\text{A} & \text{B} & \text{C} & \text{D} & \text{E}
\end{array}
\][/tex]

A. \(\frac{1}{6}\)

B. \(\frac{1}{2}\)

C. 6%

D. \(\frac{1}{3}\)

E. 1:7

Sagot :

GinnyAnsweridn
Let's solve the problem step-by-step:

1. Understanding the Problem:
We have a fair, six-sided die, and we need to determine the probability of rolling a 3.

2. Total Outcomes:
Since a six-sided dice has six faces, the total number of possible outcomes when rolling the die is 6.

3. Favorable Outcomes:
Out of these six faces, only one of them is a 3. Therefore, there is only one favorable outcome (rolling a 3).

4. Calculation of Probability:
The probability of an event is given by the ratio of the number of favorable outcomes to the total number of possible outcomes. Hence, the probability \( P \) of rolling a 3 is:

[tex]\[ P(\text{rolling a 3}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{1}{6} \][/tex]

5. Answer:
From the given options, the correct answer is:
[tex]\[ \boxed{\frac{1}{6}} \][/tex]

So, the probability of a 3 showing on the dice when it is thrown once is [tex]\(\frac{1}{6}\)[/tex], or approximately 0.16666666666666666.
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