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Two points located on [tex]\overleftrightarrow{JK}[/tex] are J(-1, -9) and K(5, 3). What is the slope of [tex]\overleftrightarrow{JK}[/tex]?

A. -2
B. [tex]-\frac{1}{2}[/tex]
C. [tex]\frac{1}{2}[/tex]
D. 2


Sagot :

To determine the slope of the line that passes through the points \( J(-1, -9) \) and \( K(5, 3) \), we use the slope formula:

[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]

Here, \((x_1, y_1) = (-1, -9)\) and \((x_2, y_2) = (5, 3)\).

Substitute the coordinates into the formula:

[tex]\[ m = \frac{3 - (-9)}{5 - (-1)} \][/tex]

Simplify the numerator and denominator:

[tex]\[ m = \frac{3 + 9}{5 + 1} \][/tex]
[tex]\[ m = \frac{12}{6} \][/tex]
[tex]\[ m = 2 \][/tex]

Thus, the slope of the line passing through points \( J \) and \( K \) is \( \boxed{2} \).

Therefore, the correct answer is:

D. 2
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