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Which line is perpendicular to a line that has a slope of [tex]$\frac{1}{2}$[/tex]?

A. Line \(AB\)
B. Line \(CD\)
C. Line \(FG\)
D. Line [tex]\(HJ\)[/tex]


Sagot :

To determine which line is perpendicular to a line with a given slope, we need to understand the relationship between the slopes of two perpendicular lines.

1. Slope Relationship: When two lines are perpendicular, the product of their slopes is \(-1\). If we denote the slope of the first line as \( m_1 \), and the slope of the perpendicular line as \( m_2 \), then:
[tex]\[ m_1 \times m_2 = -1 \][/tex]

2. Given Slope: In this problem, the slope of the first line (\( m_1 \)) is \(\frac{1}{2}\).

3. Finding the Perpendicular Slope:
[tex]\[ \frac{1}{2} \times m_2 = -1 \][/tex]

To find \( m_2 \), we solve for \( m_2 \) by isolating it on one side of the equation.

[tex]\[ m_2 = \frac{-1}{\frac{1}{2}} \][/tex]

Dividing by a fraction is equivalent to multiplying by its reciprocal. Thus,

[tex]\[ m_2 = -1 \times \frac{2}{1} \][/tex]

[tex]\[ m_2 = -2 \][/tex]

So, the slope of the line that is perpendicular to a line with slope \(\frac{1}{2}\) is \(-2\).

Final Answer: The line that is perpendicular to a line with slope \(\frac{1}{2}\) will have a slope of \(-2\). Therefore, to determine which of the lines \(AB\), \(CD\), \(FG\), and \(HJ\) is perpendicular:

- We must identify the line that has a slope of \(-2\).

Without additional details about the slopes of lines \(AB\), \(CD\), \(FG\), and \(HJ\) given in the problem, we need to match their slopes accordingly to determine which one possesses a slope of \(-2\).
Based on the slope criteria described, the correct line is the one aligned with having the slope of [tex]\(-2\)[/tex].