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In two or more complete sentences, explain how to balance the chemical equation and classify its reaction type.

[tex]\[
\text{H}_3\text{PO}_4 + \text{NaBr} \rightarrow \text{HBr} + \text{Na}_3\text{PO}_4
\][/tex]

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To balance the chemical equation [tex]\( \text{H}_3\text{PO}_4 + \text{NaBr} \rightarrow \text{HBr} + \text{Na}_3\text{PO}_4 \)[/tex], first balance the sodium (Na) atoms by placing a coefficient of 3 in front of NaBr, resulting in [tex]\( \text{H}_3\text{PO}_4 + 3\text{NaBr} \rightarrow \text{HBr} + \text{Na}_3\text{PO}_4 \)[/tex]. Then, balance the bromine (Br) atoms by placing a coefficient of 3 in front of HBr, giving [tex]\( \text{H}_3\text{PO}_4 + 3\text{NaBr} \rightarrow 3\text{HBr} + \text{Na}_3\text{PO}_4 \)[/tex]. All atoms are now balanced, and the final equation is [tex]\( \text{H}_3\text{PO}_4 + 3\text{NaBr} \rightarrow 3\text{HBr} + \text{Na}_3\text{PO}_4 \)[/tex]. This reaction is classified as a double displacement reaction, where the cations and anions of the reactants exchange places to form new products.
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