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Find the expected value of the random variable with the given probability distribution.

[tex]\[
\mu = \text{?}
\][/tex]

Do not round your answer.

\begin{tabular}{r|c}
[tex]$x$[/tex] & [tex]$P$[/tex] \\
\hline
2 & 0.10 \\
4 & 0.34 \\
6 & 0.26 \\
8 & 0.16 \\
10 & 0.09 \\
12 & 0.05 \\
\end{tabular}


Sagot :

To find the expected value (mean) of a random variable given its probability distribution, you use the formula:

[tex]\[ E(X) = \sum_{i} x_i \cdot P(x_i) \][/tex]

where \( x_i \) are the values of the random variable and \( P(x_i) \) are the corresponding probabilities. Let's go through this step-by-step using the given values.

1. List the values of \( x \) and their probabilities \( P \):

[tex]\[ x = [2, 4, 6, 8, 10, 12] \][/tex]
[tex]\[ P = [0.10, 0.34, 0.26, 0.16, 0.09, 0.05] \][/tex]

2. Multiply each value of \( x \) by its corresponding probability:

[tex]\[ 2 \times 0.10 = 0.20 \][/tex]
[tex]\[ 4 \times 0.34 = 1.36 \][/tex]
[tex]\[ 6 \times 0.26 = 1.56 \][/tex]
[tex]\[ 8 \times 0.16 = 1.28 \][/tex]
[tex]\[ 10 \times 0.09 = 0.90 \][/tex]
[tex]\[ 12 \times 0.05 = 0.60 \][/tex]

3. Sum up all the products:

[tex]\[ 0.20 + 1.36 + 1.56 + 1.28 + 0.90 + 0.60 \][/tex]

Adding these together:

[tex]\[ 0.20 + 1.36 = 1.56 \][/tex]
[tex]\[ 1.56 + 1.56 = 3.12 \][/tex]
[tex]\[ 3.12 + 1.28 = 4.40 \][/tex]
[tex]\[ 4.40 + 0.90 = 5.30 \][/tex]
[tex]\[ 5.30 + 0.60 = 5.90 \][/tex]

Thus, the expected value \( \mu \) of the random variable is:

[tex]\[ \mu = 5.9 \][/tex]