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If [tex]$f(x)=\frac{3}{x+2}-\sqrt{x-3}$[/tex], complete the following statement:

[tex]f(19)=[/tex] [tex]$\qquad$[/tex]

Answer here: __________________

Sagot :

GinnyAnsweridn
To find \( f(19) \) given the function \( f(x) = \frac{3}{x+2} - \sqrt{x-3} \), we will substitute \( x = 19 \) into the function and simplify.

1. Substitute \( x = 19 \) into the function:
[tex]\[ f(19) = \frac{3}{19 + 2} - \sqrt{19 - 3} \][/tex]

2. Simplify the denominator in the fraction:
[tex]\[ 19 + 2 = 21 \][/tex]
So,
[tex]\[ f(19) = \frac{3}{21} - \sqrt{19 - 3} \][/tex]

3. Simplify the fraction:
[tex]\[ \frac{3}{21} = \frac{1}{7} \][/tex]
So,
[tex]\[ f(19) = \frac{1}{7} - \sqrt{19 - 3} \][/tex]

4. Simplify the expression inside the square root:
[tex]\[ 19 - 3 = 16 \][/tex]
Thus,
[tex]\[ f(19) = \frac{1}{7} - \sqrt{16} \][/tex]

5. Find the square root of 16:
[tex]\[ \sqrt{16} = 4 \][/tex]
Therefore,
[tex]\[ f(19) = \frac{1}{7} - 4 \][/tex]

6. Convert 4 to a fraction with a denominator of 7 to combine the terms:
[tex]\[ 4 = \frac{28}{7} \][/tex]
Hence,
[tex]\[ f(19) = \frac{1}{7} - \frac{28}{7} \][/tex]

7. Subtract the fractions:
[tex]\[ f(19) = \frac{1 - 28}{7} = \frac{-27}{7} \][/tex]

8. Simplify the fraction:
[tex]\[ \frac{-27}{7} = -3.857142857142857 \][/tex]

Thus, the value of \( f(19) \) is:
[tex]\[ f(19) = -3.857142857142857 \][/tex]
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