Explore IDNLearn.com's extensive Q&A database and find the answers you're looking for. Our experts provide timely and precise responses to help you understand and solve any issue you face.
Sagot :
To find the average rate of change of the function \( f(x) = 2x + 9 \) from \( x_1 = -4 \) to \( x_2 = -2 \), we follow these steps:
1. Evaluate the function at \( x_1 \):
[tex]\[ f(x_1) = f(-4) = 2(-4) + 9 = -8 + 9 = 1 \][/tex]
So, \( f(-4) = 1 \).
2. Evaluate the function at \( x_2 \):
[tex]\[ f(x_2) = f(-2) = 2(-2) + 9 = -4 + 9 = 5 \][/tex]
So, \( f(-2) = 5 \).
3. Calculate the average rate of change:
The formula for the average rate of change between two points \((x_1, f(x_1))\) and \((x_2, f(x_2))\) is:
[tex]\[ \text{Average rate of change} = \frac{f(x_2) - f(x_1)}{x_2 - x_1} \][/tex]
Substituting in the values we found:
[tex]\[ \text{Average rate of change} = \frac{5 - 1}{-2 - (-4)} = \frac{5 - 1}{-2 + 4} = \frac{4}{2} = 2 \][/tex]
So, the average rate of change of [tex]\( f(x) \)[/tex] from [tex]\( x_1 = -4 \)[/tex] to [tex]\( x_2 = -2 \)[/tex] is [tex]\( \boxed{2} \)[/tex].
1. Evaluate the function at \( x_1 \):
[tex]\[ f(x_1) = f(-4) = 2(-4) + 9 = -8 + 9 = 1 \][/tex]
So, \( f(-4) = 1 \).
2. Evaluate the function at \( x_2 \):
[tex]\[ f(x_2) = f(-2) = 2(-2) + 9 = -4 + 9 = 5 \][/tex]
So, \( f(-2) = 5 \).
3. Calculate the average rate of change:
The formula for the average rate of change between two points \((x_1, f(x_1))\) and \((x_2, f(x_2))\) is:
[tex]\[ \text{Average rate of change} = \frac{f(x_2) - f(x_1)}{x_2 - x_1} \][/tex]
Substituting in the values we found:
[tex]\[ \text{Average rate of change} = \frac{5 - 1}{-2 - (-4)} = \frac{5 - 1}{-2 + 4} = \frac{4}{2} = 2 \][/tex]
So, the average rate of change of [tex]\( f(x) \)[/tex] from [tex]\( x_1 = -4 \)[/tex] to [tex]\( x_2 = -2 \)[/tex] is [tex]\( \boxed{2} \)[/tex].
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Your questions deserve reliable answers. Thanks for visiting IDNLearn.com, and see you again soon for more helpful information.