Answered

Connect with a global community of knowledgeable individuals on IDNLearn.com. Get prompt and accurate answers to your questions from our experts who are always ready to help.

Drag each tile to the table to multiply each row heading by each column heading.

\begin{tabular}{|l|l|l|}
\hline & [tex]$5t$[/tex] & [tex]$-4$[/tex] \\
\hline [tex]$4t$[/tex] & & \\
\hline [tex]$5$[/tex] & & \\
\hline
\end{tabular}

Sagot :

GinnyAnsweridn
Sure! Let's fill out the given table by multiplying each row heading by the column headings step-by-step.

First, we will set up a table to organize our products:

[tex]\[ \begin{array}{|c|c|c|} \hline & 5t & -4 \\ \hline -16t & & \\ \hline 4t & & \\ \hline 5 & & \\ \hline \end{array} \][/tex]

Now we will go row by row to calculate the products:

### First row:
- For the first cell: multiply \(-16t\) by \(5t\) to get \(\left(-16t \cdot 5t\right) = -80t^2\).
- For the second cell: multiply \(-16t\) by \(-4\) to get \(\left(-16t \cdot (-4)\right) = 64t\).

So the table now looks like this:
[tex]\[ \begin{array}{|c|c|c|} \hline & 5t & -4 \\ \hline -16t & -80t^2 & 64t \\ \hline 4t & & \\ \hline 5 & & \\ \hline \end{array} \][/tex]

### Second row:
- For the first cell: multiply \(4t\) by \(5t\) to get \(\left(4t \cdot 5t\right) = 20t^2\).
- For the second cell: multiply \(4t\) by \(-4\) to get \(\left(4t \cdot (-4)\right) = -16t\).

So the table now looks like this:
[tex]\[ \begin{array}{|c|c|c|} \hline & 5t & -4 \\ \hline -16t & -80t^2 & 64t \\ \hline 4t & 20t^2 & -16t \\ \hline 5 & & \\ \hline \end{array} \][/tex]

### Third row:
- For the first cell: multiply \(5\) by \(5t\) to get \(\left(5 \cdot 5t\right) = 25t\).
- For the second cell: multiply \(5\) by \(-4\) to get \(\left(5 \cdot (-4)\right) = -20\).

So the final table looks like this:
[tex]\[ \begin{array}{|c|c|c|} \hline & 5t & -4 \\ \hline -16t & -80t^2 & 64t \\ \hline 4t & 20t^2 & -16t \\ \hline 5 & 25t & -20 \\ \hline \end{array} \][/tex]

This is our completed table with all the products calculated!
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for answers ends at IDNLearn.com. Thank you for visiting, and we hope to assist you again soon.