IDNLearn.com: Your reliable source for finding precise answers. Get step-by-step guidance for all your technical questions from our knowledgeable community members.
Sagot :
To graph the rational function \( f(x) = \frac{(x+4)(x-2)}{x^2-4} \), we need to analyze and determine several key features of the function. Follow these steps:
### Step 1: Simplify the Equation
First, simplify the given function if possible:
[tex]\[ f(x) = \frac{(x+4)(x-2)}{x^2-4} \][/tex]
Notice that the denominator can be factored:
[tex]\[ x^2 - 4 = (x-2)(x+2) \][/tex]
So, the function becomes:
[tex]\[ f(x) = \frac{(x+4)(x-2)}{(x-2)(x+2)} \][/tex]
For \( x \neq 2 \) and \( x \neq -2 \):
[tex]\[ f(x) = \frac{x+4}{x+2} \][/tex]
### Step 2: Identify Domain Restrictions
The original function has restrictions due to the denominator:
[tex]\[ x^2 - 4 \neq 0 \implies x \neq 2 \text{ and } x \neq -2 \][/tex]
These values create vertical asymptotes. Additionally, factor cancellation makes these places where \( f(x) \) is undefined without corresponding holes in the graph.
### Step 3: Vertical Asymptotes and Holes
Since the \( x-2 \) term cancels in the numerator and denominator, it creates a hole at \( x = 2 \):
- Hole at \( x = 2 \)
Plug \( x = 2 \) into the simplified form:
[tex]\[ f(2) = \frac{2+4}{2+2} = \frac{6}{4} = 1.5 \][/tex]
So, there's a hole at \( (2, 1.5) \).
The vertical asymptote is at \( x = -2 \).
### Step 4: Find the Horizontal Asymptote
Examine the degrees of the polynomials in the numerator and the simplified denominator:
[tex]\[ \frac{x+4}{x+2} \][/tex]
Since both the numerator and denominator are of the same degree (1), the horizontal asymptote can be found by dividing the leading coefficients:
[tex]\[ \text{Horizontal asymptote: } y = \frac{1}{1} = 1 \][/tex]
### Step 5: Determine Intercepts
Y-intercept: Set \( x = 0 \):
[tex]\[ f(0) = \frac{0+4}{0+2} = \frac{4}{2} = 2 \][/tex]
So, the y-intercept is \( (0, 2) \).
X-intercepts: Set \( f(x) = 0 \):
The rational fraction is zero when the numerator is zero, i.e., \( x + 4 = 0 \):
[tex]\[ x = -4 \][/tex]
So, the x-intercept is \( (-4, 0) \).
### Step 6: Plot Points and Sketch the Graph
Now, let's gather this information to plot the graph:
1. Hole: at \( (2, 1.5) \) (draw a small open circle to indicate the hole)
2. Vertical Asymptote: \( x = -2 \) (draw a dashed vertical line)
3. Horizontal Asymptote: \( y = 1 \) (draw a dashed horizontal line)
4. Y-intercept: \( (0, 2) \)
5. X-intercept: \( (-4, 0) \)
Sketch the graph with these features in mind, approaching the asymptotes but never crossing them, and noting the hole at \( x = 2 \).
By plotting these points and asymptotes and drawing the graph smoothly according to these guidelines, you will have accurately graphed the function [tex]\( f(x) = \frac{(x+4)(x-2)}{x^2-4} \)[/tex].
### Step 1: Simplify the Equation
First, simplify the given function if possible:
[tex]\[ f(x) = \frac{(x+4)(x-2)}{x^2-4} \][/tex]
Notice that the denominator can be factored:
[tex]\[ x^2 - 4 = (x-2)(x+2) \][/tex]
So, the function becomes:
[tex]\[ f(x) = \frac{(x+4)(x-2)}{(x-2)(x+2)} \][/tex]
For \( x \neq 2 \) and \( x \neq -2 \):
[tex]\[ f(x) = \frac{x+4}{x+2} \][/tex]
### Step 2: Identify Domain Restrictions
The original function has restrictions due to the denominator:
[tex]\[ x^2 - 4 \neq 0 \implies x \neq 2 \text{ and } x \neq -2 \][/tex]
These values create vertical asymptotes. Additionally, factor cancellation makes these places where \( f(x) \) is undefined without corresponding holes in the graph.
### Step 3: Vertical Asymptotes and Holes
Since the \( x-2 \) term cancels in the numerator and denominator, it creates a hole at \( x = 2 \):
- Hole at \( x = 2 \)
Plug \( x = 2 \) into the simplified form:
[tex]\[ f(2) = \frac{2+4}{2+2} = \frac{6}{4} = 1.5 \][/tex]
So, there's a hole at \( (2, 1.5) \).
The vertical asymptote is at \( x = -2 \).
### Step 4: Find the Horizontal Asymptote
Examine the degrees of the polynomials in the numerator and the simplified denominator:
[tex]\[ \frac{x+4}{x+2} \][/tex]
Since both the numerator and denominator are of the same degree (1), the horizontal asymptote can be found by dividing the leading coefficients:
[tex]\[ \text{Horizontal asymptote: } y = \frac{1}{1} = 1 \][/tex]
### Step 5: Determine Intercepts
Y-intercept: Set \( x = 0 \):
[tex]\[ f(0) = \frac{0+4}{0+2} = \frac{4}{2} = 2 \][/tex]
So, the y-intercept is \( (0, 2) \).
X-intercepts: Set \( f(x) = 0 \):
The rational fraction is zero when the numerator is zero, i.e., \( x + 4 = 0 \):
[tex]\[ x = -4 \][/tex]
So, the x-intercept is \( (-4, 0) \).
### Step 6: Plot Points and Sketch the Graph
Now, let's gather this information to plot the graph:
1. Hole: at \( (2, 1.5) \) (draw a small open circle to indicate the hole)
2. Vertical Asymptote: \( x = -2 \) (draw a dashed vertical line)
3. Horizontal Asymptote: \( y = 1 \) (draw a dashed horizontal line)
4. Y-intercept: \( (0, 2) \)
5. X-intercept: \( (-4, 0) \)
Sketch the graph with these features in mind, approaching the asymptotes but never crossing them, and noting the hole at \( x = 2 \).
By plotting these points and asymptotes and drawing the graph smoothly according to these guidelines, you will have accurately graphed the function [tex]\( f(x) = \frac{(x+4)(x-2)}{x^2-4} \)[/tex].
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Your questions find clarity at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.