Explore IDNLearn.com's extensive Q&A database and find the answers you're looking for. Discover prompt and accurate answers from our community of experienced professionals.

Evaluate [tex]\int_0^1 \int \left(x^2 + y^2 + z^2\right) \, dx \, dy \, dz[/tex] over the volume enclosed by [tex]x^2 + y^2 + z^2 = 1[/tex].

Sagot :

To evaluate the integral \(\int_0^1 \int (x^2 + y^2 + z^2) \, dxdydz \) over the volume enclosed by the surface \( x^2 + y^2 + z^2 = 1 \), we can use spherical coordinates to simplify the computation. Here is a detailed, step-by-step solution:

1. Express the integrand and limits in spherical coordinates:
[tex]\[ x = r \sin \theta \cos \phi, \quad y = r \sin \theta \sin \phi, \quad z = r \cos \theta \][/tex]
The volume element in spherical coordinates is given by:
[tex]\[ dV = r^2 \sin \theta \, dr \, d\theta \, d\phi \][/tex]

2. Rewrite the integrand \(x^2 + y^2 + z^2\) in spherical coordinates:
[tex]\[ x^2 + y^2 + z^2 = (r \sin \theta \cos \phi)^2 + (r \sin \theta \sin \phi)^2 + (r \cos \theta)^2 \][/tex]
Simplifying this, we get:
[tex]\[ x^2 + y^2 + z^2 = r^2 (\sin^2 \theta \cos^2 \phi + \sin^2 \theta \sin^2 \phi + \cos^2 \theta) = r^2 (\sin^2 \theta (\cos^2 \phi + \sin^2 \phi) + \cos^2 \theta) = r^2 (\sin^2 \theta + \cos^2 \theta) = r^2 \][/tex]

3. Set up the integral in spherical coordinates:
[tex]\[ \iiint_V (x^2 + y^2 + z^2) \, dV \rightarrow \iiint_V r^2 \cdot r^2 \sin \theta \, dr \, d\theta \, d\phi = \iiint_V r^4 \sin \theta \, dr \, d\theta \, d\phi \][/tex]

The limits for the spherical coordinates are:
[tex]\[ 0 \leq r \leq 1, \quad 0 \leq \theta \leq \pi, \quad 0 \leq \phi \leq 2\pi \][/tex]

4. Evaluate the integral step-by-step:

First, integrate with respect to \(\phi\):
[tex]\[ \int_0^{2\pi} \int_0^{\pi} \int_0^1 r^4 \sin \theta \, dr \, d\theta \, d\phi \][/tex]
The \(\phi\) part is straightforward:
[tex]\[ \int_0^{2\pi} d\phi = 2\pi \][/tex]

Now, perform the integration with respect to \(r\):
[tex]\[ \int_0^1 r^4 \, dr = \left[ \frac{r^5}{5} \right]_0^1 = \frac{1}{5} \][/tex]

Finally, perform the integration with respect to \(\theta\):
[tex]\[ \int_0^\pi \sin \theta \, d\theta = \left[ -\cos \theta \right]_0^\pi = (-\cos \pi) - (-\cos 0) = 1 - (-1) = 2 \][/tex]

5. Combine the results:
[tex]\[ (2\pi) \cdot \left( \frac{1}{5} \right) \cdot (2) = 2\pi \cdot \frac{2}{5} = \frac{4\pi}{5} \][/tex]
Therefore, the final result is:
[tex]\[ \boxed{1.67551608191456} \][/tex]