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Find the vertical asymptote(s) of the graph of the function.

[tex]\[ h(x)=\frac{x+2}{2-x} \][/tex]

Determine the expression that needs to be set equal to 0 to find the vertical asymptote(s).

[tex]\[ \boxed{2 - x = 0} \][/tex]

(Type an expression using [tex]\( x \)[/tex] as the variable.)

Sagot :

GinnyAnsweridn
To find the vertical asymptote(s) of the function \( h(x) = \frac{x+2}{2-x} \), we need to determine the values of \( x \) that make the denominator of the function equal to 0. The vertical asymptotes occur where the denominator is zero because the function becomes undefined at these points.

Given the function \( h(x) = \frac{x+2}{2-x} \), we can identify the denominator as \( 2 - x \).

To find the vertical asymptote, we set the denominator equal to 0:
[tex]\[ 2 - x = 0 \][/tex]

Thus, the expression that needs to be set equal to 0 to find the vertical asymptote is:
[tex]\[ 2 - x = 0 \][/tex]

Therefore, the expression that needs to be set equal to 0 is:
[tex]\[ 2 - x \][/tex]
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