IDNLearn.com: Your trusted platform for finding reliable answers. Our community is here to provide the comprehensive and accurate answers you need to make informed decisions.
Sagot :
To solve the given equation \(\frac{2x - 1}{y} = \frac{w + 2}{2z}\) for \(w\), follow these steps:
1. Cross-Multiply to Eliminate the Denominators:
Given:
[tex]\[ \frac{2x - 1}{y} = \frac{w + 2}{2z} \][/tex]
Cross-multiplying both sides, we get:
[tex]\[ (2x - 1) \cdot 2z = (w + 2) \cdot y \][/tex]
This simplifies to:
[tex]\[ 2z(2x - 1) = y(w + 2) \][/tex]
2. Distribute and Expand:
Distribute \(2z\) on the left side:
[tex]\[ 4xz - 2z = y(w + 2) \][/tex]
3. Isolate \(w\) on One Side of the Equation:
Rearrange to isolate \(w\):
[tex]\[ 4xz - 2z = yw + 2y \][/tex]
Subtract \(2y\) from both sides:
[tex]\[ 4xz - 2z - 2y = yw \][/tex]
4. Solve for \(w\):
Divide both sides by \(y\) to solve for \(w\):
[tex]\[ w = \frac{4xz - 2z - 2y}{y} \][/tex]
This matches one of the choices given, specifically:
[tex]\[ w = \frac{4xz - 2z - 2y}{y} \][/tex]
Thus, the correct solution is:
[tex]\[ \boxed{w = \frac{4xz - 2z - 2y}{y}} \][/tex]
1. Cross-Multiply to Eliminate the Denominators:
Given:
[tex]\[ \frac{2x - 1}{y} = \frac{w + 2}{2z} \][/tex]
Cross-multiplying both sides, we get:
[tex]\[ (2x - 1) \cdot 2z = (w + 2) \cdot y \][/tex]
This simplifies to:
[tex]\[ 2z(2x - 1) = y(w + 2) \][/tex]
2. Distribute and Expand:
Distribute \(2z\) on the left side:
[tex]\[ 4xz - 2z = y(w + 2) \][/tex]
3. Isolate \(w\) on One Side of the Equation:
Rearrange to isolate \(w\):
[tex]\[ 4xz - 2z = yw + 2y \][/tex]
Subtract \(2y\) from both sides:
[tex]\[ 4xz - 2z - 2y = yw \][/tex]
4. Solve for \(w\):
Divide both sides by \(y\) to solve for \(w\):
[tex]\[ w = \frac{4xz - 2z - 2y}{y} \][/tex]
This matches one of the choices given, specifically:
[tex]\[ w = \frac{4xz - 2z - 2y}{y} \][/tex]
Thus, the correct solution is:
[tex]\[ \boxed{w = \frac{4xz - 2z - 2y}{y}} \][/tex]
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. IDNLearn.com is committed to your satisfaction. Thank you for visiting, and see you next time for more helpful answers.