At IDNLearn.com, find answers to your most pressing questions from experts and enthusiasts alike. Join our knowledgeable community and access a wealth of reliable answers to your most pressing questions.
Sagot :
To find the asymptote parallel to the y-axis for the curve given by the equation
[tex]\[ (x^2 + y^2) x - a y^2 = 0, \][/tex]
we can start by rearranging the equation to make it easier to analyze:
[tex]\[ x^3 + x y^2 - a y^2 = 0. \][/tex]
Here, we want to find the values of \( x \) such that, as \( y \) tends to infinity, the equation describes an asymptote parallel to the y-axis. Essentially, we seek vertical asymptotes where \( x \) tends to some constant value while \( y \) goes to infinity.
To identify such points, we need to analyze how \( x \) behaves as \( y \) grows very large. Suppose \( y \) is very large, we would expect that terms including \( y^2 \) are dominant. Let's re-examine the equation under this assumption:
[tex]\[ x^3 + (x - a)y^2 = 0. \][/tex]
Dividing through by \( y^2 \):
[tex]\[ \frac{x^3}{y^2} + (x - a) = 0. \][/tex]
Since \( y \) is very large, the term \(\frac{x^3}{y^2}\) becomes very small and in the limit can be considered approaching zero. Thus, the dominant terms reduce to:
[tex]\[ x - a \approx 0, \][/tex]
which implies:
[tex]\[ x \approx a. \][/tex]
Thus, we determined that as \( y \) approaches infinity, \( x \) approaches the constant \( a \), suggesting that \( x = a \) is a vertical asymptote.
Hence, the correct option is:
(d) [tex]\( x = a \)[/tex].
[tex]\[ (x^2 + y^2) x - a y^2 = 0, \][/tex]
we can start by rearranging the equation to make it easier to analyze:
[tex]\[ x^3 + x y^2 - a y^2 = 0. \][/tex]
Here, we want to find the values of \( x \) such that, as \( y \) tends to infinity, the equation describes an asymptote parallel to the y-axis. Essentially, we seek vertical asymptotes where \( x \) tends to some constant value while \( y \) goes to infinity.
To identify such points, we need to analyze how \( x \) behaves as \( y \) grows very large. Suppose \( y \) is very large, we would expect that terms including \( y^2 \) are dominant. Let's re-examine the equation under this assumption:
[tex]\[ x^3 + (x - a)y^2 = 0. \][/tex]
Dividing through by \( y^2 \):
[tex]\[ \frac{x^3}{y^2} + (x - a) = 0. \][/tex]
Since \( y \) is very large, the term \(\frac{x^3}{y^2}\) becomes very small and in the limit can be considered approaching zero. Thus, the dominant terms reduce to:
[tex]\[ x - a \approx 0, \][/tex]
which implies:
[tex]\[ x \approx a. \][/tex]
Thus, we determined that as \( y \) approaches infinity, \( x \) approaches the constant \( a \), suggesting that \( x = a \) is a vertical asymptote.
Hence, the correct option is:
(d) [tex]\( x = a \)[/tex].
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. For dependable and accurate answers, visit IDNLearn.com. Thanks for visiting, and see you next time for more helpful information.