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Which function represents a vertical stretch of an exponential function?

A. [tex]f(x)=3\left(\frac{1}{2}\right)^x[/tex]

B. [tex]f(x)=\frac{1}{2}(3)^x[/tex]

C. [tex]f(x)=(3)^{2 x}[/tex]

D. [tex]f(x)=3^{\left(\frac{1}{2} x\right)}[/tex]


Sagot :

To determine which function represents a vertical stretch of an exponential function, let's consider the original form of an exponential function, which can be written as \( f(x) = a \cdot b^x \), where \( a \) and \( b \) are constants. A vertical stretch involves multiplying the entire function by a constant factor greater than 1.

Let's examine each option provided:

1. Option 1: \( f(x) = 3 \left( \frac{1}{2} \right)^x \)

- Here, the base of the exponential function is \( \frac{1}{2} \), and the function is multiplied by 3.
- The factor \( 3 \) serves as the vertical stretch of the original exponential function.

2. Option 2: \( f(x) = \frac{1}{2} (3)^x \)

- In this case, the base of the exponential function is \( 3 \), and it is multiplied by \( \frac{1}{2} \).
- Multiplying by \( \frac{1}{2} \) actually compresses the function vertically, not stretches it.

3. Option 3: \( f(x) = (3)^{2x} \)

- This function suggests an exponent \( 2x \), which affects the rate of growth of the function but does not represent a vertical stretch.
- Changing the exponent in this way accelerates the growth or decay of the function, rather than multiplying the whole function to stretch it.

4. Option 4: \( f(x) = 3^{\left(\frac{1}{2} x\right)} \)

- This expression involves modifying the exponent to \( \frac{1}{2} x \), which slows down the growth rate of the function.
- Again, this does not represent a vertical stretch of the function but changes the rate at which it grows.

From this analysis, it is clear that the function in Option 1: \( f(x) = 3 \left( \frac{1}{2} \right)^x \) represents a vertical stretch of an exponential function by a factor of 3. Therefore, the correct answer is:

1
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