Answered

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The weight of Sarad is 550 N and Nirmal is 300 N. Sarad
and Nirmal are playing see-saw. How far does the Nirmal sit
from the centre to balance the Sarad who sits at a distance
of 1.5 m from the center. (Ans: 2.75 in)

Sagot :

Nengikimidn

Answer:

To balance the seesaw, the product of weight and distance from the fulcrum (center) must be equal for both Sarad and Nirmal. Let's denote the distance Nirmal sits from the center as d.

Here's the equation to find d:

weight_Sarad * distance_Sarad = weight_Nirmal * d

Plugging in the known values:

550 N * 1.5 m = 300 N * d

Solving for d:

d = (550 N * 1.5 m) / 300 N

d = 2.75 m

Since the question asks for the distance in meters, the answer is 2.75 meters.

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