Connect with experts and get insightful answers on IDNLearn.com. Get comprehensive and trustworthy answers to all your questions from our knowledgeable community members.

Consider the quadratic function:
[tex]\[ f(x) = x^2 - 8x - 9 \][/tex]

What is the vertex of the function?

Vertex: [tex]\[ \left( \frac{-b}{2a}, f\left(\frac{-b}{2a}\right) \right) \][/tex]


Sagot :

To find the vertex of the quadratic function \( f(x) = x^2 - 8x - 9 \), we will use the vertex formula for a parabola given by \( f(x) = ax^2 + bx + c \):

The formula for the x-coordinate of the vertex is:
[tex]\[ x = \frac{-b}{2a} \][/tex]

In our function, we identify \( a = 1 \), \( b = -8 \), and \( c = -9 \).

First, we calculate the x-coordinate of the vertex:

[tex]\[ x = \frac{-(-8)}{2 \cdot 1} = \frac{8}{2} = 4 \][/tex]

Next, we need to find the y-coordinate of the vertex by substituting \( x = 4 \) back into the original function \( f(x) \):

[tex]\[ f(4) = (4)^2 - 8(4) - 9 \][/tex]

We calculate each term step-by-step:

[tex]\[ (4)^2 = 16 \][/tex]
[tex]\[ -8(4) = -32 \][/tex]

So plugging these back into the function:

[tex]\[ f(4) = 16 - 32 - 9 \][/tex]

Now, we simplify this:

[tex]\[ 16 - 32 = -16 \][/tex]
[tex]\[ -16 - 9 = -25 \][/tex]

Therefore, the y-coordinate of the vertex is:

[tex]\[ f(4) = -25 \][/tex]

Hence, the vertex of the function \( f(x) = x^2 - 8x - 9 \) is:

[tex]\[ (4, -25) \][/tex]

So, the vertex of the function is [tex]\(\left(\frac{-b}{2a}, f\left(\frac{-b}{2a}\right)\right) = (4, -25)\)[/tex].
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.