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59 mol of Ca3(PO4)2 is used during the experiment. What is the theoretical yield for the product produced in the greatest quantity?

Sagot :

BrotherGokuidn

Answer:

19258.4g of Ca3(PO4)2 produced from 59 mol,

Explanation:

Theoretical Yield

Theoretical Yield refers to the highest mass that can be produced in a specific reaction. When given the number of moles of the molecule, the mass can be found with the help of the molar mass.

Molar Mass

Ca3(PO4)2

3 Ca = 3(40.078) = 120.234 g/mol

2 P = 2(39.0983) = 78.1878 g/mol

8 O = 8(15.999) = 127.992 g/mol

Total mass = 120.234 + 78.1878 + 127.992 = 326.4138 g/mol (3 decimals lowest i.e. 6 s.f.)

Knowing that the molar mass is derived from the formula m/n, where m is the mass and n is the number of moles, simply multiply each side by the number of moles to find the mass.

M = m/n  ->   M*n = m

M = 326.4138g/mol

n = 59 mol

m = 59*326.4138 = 19258.4142g

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