IDNLearn.com provides a reliable platform for finding accurate and timely answers. Join our Q&A platform to access reliable and detailed answers from experts in various fields.
Sagot :
To determine the orbital period of Jupiter using the stated equation \( P^2 = A^3 \), where \( A \) is the semi-major axis of Jupiter's orbit in astronomical units (AU) and \( P \) is the orbital period in years, follow these steps:
1. Identify the Given Value:
- The semi-major axis \( A \) for Jupiter is 5.2 AU.
2. Calculate \( A^3 \):
[tex]\[ A^3 = 5.2^3 = 140.608 \][/tex]
3. Set Up the Equation \( P^2 = A^3 \):
[tex]\[ P^2 = 140.608 \][/tex]
4. Solve for \( P \) by Taking the Square Root of Both Sides:
[tex]\[ P = \sqrt{140.608} \approx 11.8578 \][/tex]
5. Examine the Multiple-Choice Options:
- The options provided are 5 years, 11 years, 110 years, and 500 years.
6. Determine the Closest Match to the Calculated \( P \):
- The closest value to \( 11.8578 \) among the given choices is 11 years.
Therefore, the orbital period of Jupiter is approximately 11 years.
1. Identify the Given Value:
- The semi-major axis \( A \) for Jupiter is 5.2 AU.
2. Calculate \( A^3 \):
[tex]\[ A^3 = 5.2^3 = 140.608 \][/tex]
3. Set Up the Equation \( P^2 = A^3 \):
[tex]\[ P^2 = 140.608 \][/tex]
4. Solve for \( P \) by Taking the Square Root of Both Sides:
[tex]\[ P = \sqrt{140.608} \approx 11.8578 \][/tex]
5. Examine the Multiple-Choice Options:
- The options provided are 5 years, 11 years, 110 years, and 500 years.
6. Determine the Closest Match to the Calculated \( P \):
- The closest value to \( 11.8578 \) among the given choices is 11 years.
Therefore, the orbital period of Jupiter is approximately 11 years.
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Thank you for visiting IDNLearn.com. We’re here to provide clear and concise answers, so visit us again soon.