IDNLearn.com: Your trusted platform for finding reliable answers. Find reliable solutions to your questions quickly and easily with help from our experienced experts.
Sagot :
To determine the compound interest on a principal amount of ₹312,121 over 2 years at an annual interest rate of 12%, we can use the compound interest formula. Here's the step-by-step process:
### 1. Understanding the Variables:
- Principal (P): ₹312,121
- Annual Interest Rate (r): 12% (or 0.12 in decimal form)
- Time (t): 2 years
- Number of Times Interest is Compounded Per Year (n): Since it is compounded annually, \( n = 1 \)
### 2. Compound Interest Formula:
The formula to calculate compound interest when compounded annually is given by:
[tex]\[ CI = P \left(1 + \frac{r}{n}\right)^{nt} - P \][/tex]
### 3. Plugging in the Values:
Substitute the variables into the formula:
[tex]\[ CI = 312121 \left(1 + \frac{0.12}{1}\right)^{1 \times 2} - 312121 \][/tex]
### 4. Simplifying the Expression:
First, calculate the term inside the parentheses:
[tex]\[ 1 + \frac{0.12}{1} = 1 + 0.12 = 1.12 \][/tex]
Now raise this to the power of \( nt \):
[tex]\[ (1.12)^{2} \][/tex]
Calculate \(1.12\) raised to the power of \(2\):
[tex]\[ (1.12)^2 = 1.2544 \][/tex]
Next, multiply the principal amount by this result:
[tex]\[ 312121 \times 1.2544 \][/tex]
### 5. Further Calculation:
[tex]\[ 312121 \times 1.2544 = 391524.5824 \][/tex]
Now, subtract the principal amount from this result to find the compound interest:
[tex]\[ 391524.5824 - 312121 = 79403.5824 \][/tex]
### 6. Final Result:
The compound interest on ₹312,121 over 2 years at an annual interest rate of 12% is approximately ₹79,403.58.
---
So, the answer is ₹79,403.58.
### 1. Understanding the Variables:
- Principal (P): ₹312,121
- Annual Interest Rate (r): 12% (or 0.12 in decimal form)
- Time (t): 2 years
- Number of Times Interest is Compounded Per Year (n): Since it is compounded annually, \( n = 1 \)
### 2. Compound Interest Formula:
The formula to calculate compound interest when compounded annually is given by:
[tex]\[ CI = P \left(1 + \frac{r}{n}\right)^{nt} - P \][/tex]
### 3. Plugging in the Values:
Substitute the variables into the formula:
[tex]\[ CI = 312121 \left(1 + \frac{0.12}{1}\right)^{1 \times 2} - 312121 \][/tex]
### 4. Simplifying the Expression:
First, calculate the term inside the parentheses:
[tex]\[ 1 + \frac{0.12}{1} = 1 + 0.12 = 1.12 \][/tex]
Now raise this to the power of \( nt \):
[tex]\[ (1.12)^{2} \][/tex]
Calculate \(1.12\) raised to the power of \(2\):
[tex]\[ (1.12)^2 = 1.2544 \][/tex]
Next, multiply the principal amount by this result:
[tex]\[ 312121 \times 1.2544 \][/tex]
### 5. Further Calculation:
[tex]\[ 312121 \times 1.2544 = 391524.5824 \][/tex]
Now, subtract the principal amount from this result to find the compound interest:
[tex]\[ 391524.5824 - 312121 = 79403.5824 \][/tex]
### 6. Final Result:
The compound interest on ₹312,121 over 2 years at an annual interest rate of 12% is approximately ₹79,403.58.
---
So, the answer is ₹79,403.58.
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for visiting IDNLearn.com. We’re here to provide dependable answers, so visit us again soon.