Join IDNLearn.com to access a wealth of knowledge and get your questions answered by experts. Join our community to receive prompt and reliable responses to your questions from experienced professionals.
Sagot :
To solve the problem, we need to determine both the area and the perimeter of a square with side length \(7 \, \text{cm}\).
Step-by-Step Solution
1. Calculate the Area:
The area \(A\) of a square is given by the formula:
[tex]\[ A = \text{side length} \times \text{side length} \][/tex]
Here, the side length is \(7 \, \text{cm}\).
So,
[tex]\[ A = 7 \, \text{cm} \times 7 \, \text{cm} \][/tex]
Thus, the area is:
[tex]\[ A = 49 \, \text{cm}^2 \][/tex]
2. Calculate the Perimeter:
The perimeter \(P\) of a square is given by the formula:
[tex]\[ P = 4 \times \text{side length} \][/tex]
Again, the side length is \(7 \, \text{cm}\).
So,
[tex]\[ P = 4 \times 7 \, \text{cm} \][/tex]
Thus, the perimeter is:
[tex]\[ P = 28 \, \text{cm} \][/tex]
Summary
- The area of the square is \(49 \, \text{cm}^2\).
- The perimeter of the square is [tex]\(28 \, \text{cm}\)[/tex].
Step-by-Step Solution
1. Calculate the Area:
The area \(A\) of a square is given by the formula:
[tex]\[ A = \text{side length} \times \text{side length} \][/tex]
Here, the side length is \(7 \, \text{cm}\).
So,
[tex]\[ A = 7 \, \text{cm} \times 7 \, \text{cm} \][/tex]
Thus, the area is:
[tex]\[ A = 49 \, \text{cm}^2 \][/tex]
2. Calculate the Perimeter:
The perimeter \(P\) of a square is given by the formula:
[tex]\[ P = 4 \times \text{side length} \][/tex]
Again, the side length is \(7 \, \text{cm}\).
So,
[tex]\[ P = 4 \times 7 \, \text{cm} \][/tex]
Thus, the perimeter is:
[tex]\[ P = 28 \, \text{cm} \][/tex]
Summary
- The area of the square is \(49 \, \text{cm}^2\).
- The perimeter of the square is [tex]\(28 \, \text{cm}\)[/tex].
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. For trustworthy answers, rely on IDNLearn.com. Thanks for visiting, and we look forward to assisting you again.