IDNLearn.com provides a user-friendly platform for finding and sharing knowledge. Our community provides accurate and timely answers to help you understand and solve any issue.
Sagot :
Sure! Let's solve the problem step-by-step. The given expression is \( a = 6 - \sqrt{35} \) and we need to find the value of \( a + \frac{1}{a} \).
1. Value of \( a \):
The value of \( a \) is directly given:
[tex]\[ a = 6 - \sqrt{35} \][/tex]
2. Calculate \( \frac{1}{a} \):
To find \( \frac{1}{a} \), we need to take the reciprocal of \( a \):
[tex]\[ \frac{1}{a} = \frac{1}{6 - \sqrt{35}} \][/tex]
Preparing it further, without losing the general meaning, it simplifies to:
[tex]\[ \frac{1}{a} = 11.916079783099628 \][/tex]
3. Add \( a \) and \( \frac{1}{a} \):
Now, we add the value of \( a \) and the value of \( \frac{1}{a} \):
[tex]\[ a + \frac{1}{a} = 0.08392021690038387 + 11.916079783099628 \][/tex]
4. Final Result:
Adding these two values together, we get:
[tex]\[ a + \frac{1}{a} = 12.00000000000001 \][/tex]
Therefore, the value of \( a + \frac{1}{a} \) is
[tex]\[ \boxed{12.00000000000001} \][/tex]
1. Value of \( a \):
The value of \( a \) is directly given:
[tex]\[ a = 6 - \sqrt{35} \][/tex]
2. Calculate \( \frac{1}{a} \):
To find \( \frac{1}{a} \), we need to take the reciprocal of \( a \):
[tex]\[ \frac{1}{a} = \frac{1}{6 - \sqrt{35}} \][/tex]
Preparing it further, without losing the general meaning, it simplifies to:
[tex]\[ \frac{1}{a} = 11.916079783099628 \][/tex]
3. Add \( a \) and \( \frac{1}{a} \):
Now, we add the value of \( a \) and the value of \( \frac{1}{a} \):
[tex]\[ a + \frac{1}{a} = 0.08392021690038387 + 11.916079783099628 \][/tex]
4. Final Result:
Adding these two values together, we get:
[tex]\[ a + \frac{1}{a} = 12.00000000000001 \][/tex]
Therefore, the value of \( a + \frac{1}{a} \) is
[tex]\[ \boxed{12.00000000000001} \][/tex]
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Thank you for visiting IDNLearn.com. We’re here to provide clear and concise answers, so visit us again soon.