Great! Let's walk through the problem step-by-step together.
1. Determine the weight of the first jar:
- Andrea's first jar weighs \( 3 \frac{1}{3} \) ounces.
- To write it as an improper fraction: \( 3 \frac{1}{3} = 3 + \frac{1}{3} \).
- Converting \( 3 \frac{1}{3} \) to a decimal: \( 3 + \frac{1}{3} = 3.333\overline{3} \) (or approximately 3.3333).
2. Determine the weight of the second jar:
- The second jar weighs \( \frac{1}{2} \) ounce more than the first jar.
- Add \( \frac{1}{2} \) (which is 0.5) to the weight of the first jar.
- The weight of the second jar: \( 3.333\overline{3} + 0.5 = 3.833\overline{3} \) (or approximately 3.8333).
3. Calculate the total weight of both jars combined:
- Add the weight of the first jar \( 3.333\overline{3} \) and the weight of the second jar \( 3.833\overline{3} \).
- The total weight of the two jars: \( 3.333\overline{3} + 3.833\overline{3} = 7.166\overline{6} \) (or approximately 7.1667).
So, filling in the correct spaces:
- The weight of the first jar is approximately 3.3333 ounces.
- The weight of the second jar is approximately 3.8333 ounces.
- The total weight of the two jars together is approximately 7.1667 ounces.
