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if 8^y=16^y+2 what is the value of y

Sagot :

Laureneonidn

Answer:

Step-by-step explanation:

First, let’s get the base to be the same number. Then we can look at the exponents and compare!

8^y = 16^(y+2)

2^3y = 2^4(y+2)

3y = 4(y+2)

3y = 4y + 8

-y = 8

y = -8


Hope this helps!

Step-by-step explanation:

[tex]take \: log_{2} \: both \: side \\ \\ y \: log_{2}(8) = y log_{2}(16) + log2 \\ \\ y \times 3 = y \times 4 + 1 \\ \\ 4y - 3y = - 1 \\ \\ y = - 1[/tex]

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