IDNLearn.com makes it easy to get reliable answers from experts and enthusiasts alike. Discover trustworthy solutions to your questions quickly and accurately with help from our dedicated community of experts.

Multi-Part Question

The table below shows how much time some people spent exercising yesterday.

[tex]\[
\begin{tabular}{|c|c|}
\hline
Time spent, [tex]$x$[/tex] (minutes) & Frequency \\
\hline
[tex]$0 \ \textless \ x \leq 10$[/tex] & 18 \\
\hline
[tex]$10 \ \textless \ x \leq 20$[/tex] & 14 \\
\hline
[tex]$20 \ \textless \ x \leq 30$[/tex] & 3 \\
\hline
[tex]$30 \ \textless \ x \leq 40$[/tex] & 16 \\
\hline
[tex]$40 \ \textless \ x \leq 50$[/tex] & 21 \\
\hline
[tex]$50 \ \textless \ x \leq 60$[/tex] & 7 \\
\hline
\end{tabular}
\][/tex]


Sagot :

To solve this question, we need to analyze the given data about the time people spent exercising and calculate the total number of people. Here is a step-by-step explanation:

1. Understand the Data:
- The time intervals (in minutes) and their corresponding frequencies are given in a table.
- The frequencies represent the number of people who exercised for the given time intervals.

2. Identify the Midpoints of the Intervals:
- For easier calculations, we'll use the midpoint of each interval. The midpoints can be calculated as follows:
- For \(0 < x \leq 10\), the midpoint is \(\frac{0+10}{2} = 5\) minutes.
- For \(10 < x \leq 20\), the midpoint is \(\frac{10+20}{2} = 15\) minutes.
- For \(20 < x \leq 30\), the midpoint is \(\frac{20+30}{2} = 25\) minutes.
- For \(30 < x \leq 40\), the midpoint is \(\frac{30+40}{2} = 35\) minutes.
- For \(40 < x \leq 50\), the midpoint is \(\frac{40+50}{2} = 45\) minutes.
- For \(50 < x \leq 60\), the midpoint is \(\frac{50+60}{2} = 55\) minutes.

3. Summarize the Data:
- Midpoints: \( [5, 15, 25, 35, 45, 55] \)
- Frequencies: \( [18, 14, 3, 16, 21, 7] \)

4. Calculate the Total Number of People:
- The total number of people is the sum of all the frequencies.

[tex]\[ \begin{aligned} \text{Total number of people} & = 18 + 14 + 3 + 16 + 21 + 7 \\ & = 79 \end{aligned} \][/tex]

5. Solution Summary:
- We found the midpoints of each interval: \([5, 15, 25, 35, 45, 55]\).
- The frequencies are given as: \([18, 14, 3, 16, 21, 7]\).
- The total number of people who exercised is 79.

Therefore, the detailed results are the midpoints of the intervals, the frequencies, and the total number of people, which are:
[tex]\[ ([5, 15, 25, 35, 45, 55], [18, 14, 3, 16, 21, 7], 79) \][/tex]