Get expert advice and insights on any topic with IDNLearn.com. Find reliable solutions to your questions quickly and accurately with help from our dedicated community of experts.
Sagot :
To find the error Jamal made in simplifying the expression [tex]\(\sqrt{75 x^5 y^8}\)[/tex], let's break down the process step-by-step correctly.
1. Initial Expression:
[tex]\[ \sqrt{75 x^5 y^8} \][/tex]
2. Factor Inside the Square Root:
[tex]\[ 75 = 3 \times 25 \quad \text{so,} \quad 75 x^5 y^8 = 3 \times 25 \times x^4 \times x \times y^8 \][/tex]
Therefore:
[tex]\[ \sqrt{75 x^5 y^8} = \sqrt{3 \times 25 \times x^4 \times x \times y^8} \][/tex]
3. Separate the Radicals:
We can separate the square root of a product into the product of square roots:
[tex]\[ \sqrt{3 \times 25 \times x^4 \times x \times y^8} = \sqrt{3} \times \sqrt{25} \times \sqrt{x^4} \times \sqrt{x} \times \sqrt{y^8} \][/tex]
4. Simplify Each Term:
- [tex]\(\sqrt{25} = 5\)[/tex]
- [tex]\(\sqrt{x^4} = x^2\)[/tex], since [tex]\(x^4\)[/tex] is a perfect square.
- [tex]\(\sqrt{y^8} = y^4\)[/tex], since [tex]\(y^8\)[/tex] is a perfect square.
So we get:
[tex]\[ \sqrt{3} \times 5 \times x^2 \times \sqrt{x} \times y^4 \][/tex]
5. Combine Terms Outside the Radical:
[tex]\[ 5x^2y^4 \sqrt{3x} \][/tex]
However, Jamal simplified the expression as:
[tex]\[ 5 x^2 y^2 \sqrt{3 x} \][/tex]
Now, compare this to the correct simplification:
[tex]\[ 5 x^2 y^4 \sqrt{3 x} \][/tex]
Jamal's error is in the power of [tex]\(y\)[/tex]. He wrote the square root of [tex]\(y^8\)[/tex] as [tex]\(y^2\)[/tex] instead of [tex]\(y^4\)[/tex].
### Conclusion
The correct option is:
"He should have written the square root of [tex]\(y^8\)[/tex] in the answer as [tex]\(y^4\)[/tex], not [tex]\(y^2\)[/tex]."
1. Initial Expression:
[tex]\[ \sqrt{75 x^5 y^8} \][/tex]
2. Factor Inside the Square Root:
[tex]\[ 75 = 3 \times 25 \quad \text{so,} \quad 75 x^5 y^8 = 3 \times 25 \times x^4 \times x \times y^8 \][/tex]
Therefore:
[tex]\[ \sqrt{75 x^5 y^8} = \sqrt{3 \times 25 \times x^4 \times x \times y^8} \][/tex]
3. Separate the Radicals:
We can separate the square root of a product into the product of square roots:
[tex]\[ \sqrt{3 \times 25 \times x^4 \times x \times y^8} = \sqrt{3} \times \sqrt{25} \times \sqrt{x^4} \times \sqrt{x} \times \sqrt{y^8} \][/tex]
4. Simplify Each Term:
- [tex]\(\sqrt{25} = 5\)[/tex]
- [tex]\(\sqrt{x^4} = x^2\)[/tex], since [tex]\(x^4\)[/tex] is a perfect square.
- [tex]\(\sqrt{y^8} = y^4\)[/tex], since [tex]\(y^8\)[/tex] is a perfect square.
So we get:
[tex]\[ \sqrt{3} \times 5 \times x^2 \times \sqrt{x} \times y^4 \][/tex]
5. Combine Terms Outside the Radical:
[tex]\[ 5x^2y^4 \sqrt{3x} \][/tex]
However, Jamal simplified the expression as:
[tex]\[ 5 x^2 y^2 \sqrt{3 x} \][/tex]
Now, compare this to the correct simplification:
[tex]\[ 5 x^2 y^4 \sqrt{3 x} \][/tex]
Jamal's error is in the power of [tex]\(y\)[/tex]. He wrote the square root of [tex]\(y^8\)[/tex] as [tex]\(y^2\)[/tex] instead of [tex]\(y^4\)[/tex].
### Conclusion
The correct option is:
"He should have written the square root of [tex]\(y^8\)[/tex] in the answer as [tex]\(y^4\)[/tex], not [tex]\(y^2\)[/tex]."
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for answers ends at IDNLearn.com. Thank you for visiting, and we hope to assist you again soon.