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To find the solutions to the quadratic equation [tex]\( 2x^2 + 10x - 12 = 0 \)[/tex], proceed as follows:
1. Write the equation in standard form:
The given equation [tex]\( 2x^2 + 10x - 12 = 0 \)[/tex] is already in standard quadratic form, which is [tex]\( ax^2 + bx + c = 0 \)[/tex], where [tex]\( a = 2 \)[/tex], [tex]\( b = 10 \)[/tex], and [tex]\( c = -12 \)[/tex].
2. Solve the quadratic equation:
By solving the quadratic equation, we find the values of [tex]\( x \)[/tex] that satisfy the equation.
3. Identify the solutions:
From the previous detailed solving steps (not shown here), we know that the solutions to the quadratic equation [tex]\( 2x^2 + 10x - 12 = 0 \)[/tex] are:
[tex]\[ x = -6 \quad \text{and} \quad x = 1 \][/tex]
Therefore, the correct solutions to the equation [tex]\( 2x^2 + 10x - 12 = 0 \)[/tex] are:
- [tex]\( x = -6 \)[/tex]
- [tex]\( x = 1 \)[/tex]
The correct answers to select would be:
- [tex]\( x = -6 \)[/tex]
- [tex]\( x = 1 \)[/tex]
1. Write the equation in standard form:
The given equation [tex]\( 2x^2 + 10x - 12 = 0 \)[/tex] is already in standard quadratic form, which is [tex]\( ax^2 + bx + c = 0 \)[/tex], where [tex]\( a = 2 \)[/tex], [tex]\( b = 10 \)[/tex], and [tex]\( c = -12 \)[/tex].
2. Solve the quadratic equation:
By solving the quadratic equation, we find the values of [tex]\( x \)[/tex] that satisfy the equation.
3. Identify the solutions:
From the previous detailed solving steps (not shown here), we know that the solutions to the quadratic equation [tex]\( 2x^2 + 10x - 12 = 0 \)[/tex] are:
[tex]\[ x = -6 \quad \text{and} \quad x = 1 \][/tex]
Therefore, the correct solutions to the equation [tex]\( 2x^2 + 10x - 12 = 0 \)[/tex] are:
- [tex]\( x = -6 \)[/tex]
- [tex]\( x = 1 \)[/tex]
The correct answers to select would be:
- [tex]\( x = -6 \)[/tex]
- [tex]\( x = 1 \)[/tex]
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