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To find the value of [tex]\((f - g)(2)\)[/tex] when [tex]\(f(x) = 3x^2 + 1\)[/tex] and [tex]\(g(x) = 1 - x\)[/tex], let's go through it step-by-step.
1. Evaluate [tex]\(f(2)\)[/tex]:
Given [tex]\(f(x) = 3x^2 + 1\)[/tex],
[tex]\[ f(2) = 3(2)^2 + 1 = 3 \cdot 4 + 1 = 12 + 1 = 13. \][/tex]
2. Evaluate [tex]\(g(2)\)[/tex]:
Given [tex]\(g(x) = 1 - x\)[/tex],
[tex]\[ g(2) = 1 - 2 = -1. \][/tex]
3. Calculate [tex]\((f - g)(2)\)[/tex]:
[tex]\[ (f - g)(2) = f(2) - g(2). \][/tex]
Substitute the values found:
[tex]\[ (f - g)(2) = 13 - (-1) = 13 + 1 = 14. \][/tex]
Hence, the value of [tex]\((f - g)(2)\)[/tex] is [tex]\(\boxed{14}\)[/tex].
1. Evaluate [tex]\(f(2)\)[/tex]:
Given [tex]\(f(x) = 3x^2 + 1\)[/tex],
[tex]\[ f(2) = 3(2)^2 + 1 = 3 \cdot 4 + 1 = 12 + 1 = 13. \][/tex]
2. Evaluate [tex]\(g(2)\)[/tex]:
Given [tex]\(g(x) = 1 - x\)[/tex],
[tex]\[ g(2) = 1 - 2 = -1. \][/tex]
3. Calculate [tex]\((f - g)(2)\)[/tex]:
[tex]\[ (f - g)(2) = f(2) - g(2). \][/tex]
Substitute the values found:
[tex]\[ (f - g)(2) = 13 - (-1) = 13 + 1 = 14. \][/tex]
Hence, the value of [tex]\((f - g)(2)\)[/tex] is [tex]\(\boxed{14}\)[/tex].
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