Connect with a global community of experts on IDNLearn.com. Join our community to receive prompt, thorough responses from knowledgeable experts.
Sagot :
To solve the expression [tex]\(\sqrt{-98}\)[/tex], we need to follow a series of steps that involve understanding the properties of square roots and imaginary numbers.
1. Identifying the Imaginary Unit:
We know that [tex]\(\sqrt{-1} = i\)[/tex], where [tex]\(i\)[/tex] is the imaginary unit.
2. Separating the Components:
Given the expression [tex]\(\sqrt{-98}\)[/tex], we can rewrite it as:
[tex]\[ \sqrt{-98} = \sqrt{98} \cdot \sqrt{-1} = \sqrt{98} \cdot i \][/tex]
3. Simplifying the Square Root of 98:
Next, let's simplify [tex]\(\sqrt{98}\)[/tex]. We need to break this down into its prime factors:
[tex]\[ 98 = 2 \times 49 = 2 \times 7^2 \][/tex]
Therefore,
[tex]\[ \sqrt{98} = \sqrt{2 \times 7^2} \][/tex]
4. Using the Property of Square Roots:
We can further simplify using the property [tex]\(\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}\)[/tex]:
[tex]\[ \sqrt{98} = \sqrt{2 \times 7^2} = \sqrt{2} \times \sqrt{7^2} = \sqrt{2} \times 7 \][/tex]
5. Combining with the Imaginary Unit:
Substituting this back into our expression:
[tex]\[ \sqrt{-98} = \sqrt{98} \cdot i = 7 \sqrt{2} \cdot i = 7i\sqrt{2} \][/tex]
Thus, the expression [tex]\(\sqrt{-98}\)[/tex] simplifies to [tex]\(7i\sqrt{2}\)[/tex].
Therefore, the correct option is:
[tex]\[ \boxed{7i\sqrt{2}} \][/tex]
So the answer is C: [tex]\(7 i \sqrt{2}\)[/tex].
1. Identifying the Imaginary Unit:
We know that [tex]\(\sqrt{-1} = i\)[/tex], where [tex]\(i\)[/tex] is the imaginary unit.
2. Separating the Components:
Given the expression [tex]\(\sqrt{-98}\)[/tex], we can rewrite it as:
[tex]\[ \sqrt{-98} = \sqrt{98} \cdot \sqrt{-1} = \sqrt{98} \cdot i \][/tex]
3. Simplifying the Square Root of 98:
Next, let's simplify [tex]\(\sqrt{98}\)[/tex]. We need to break this down into its prime factors:
[tex]\[ 98 = 2 \times 49 = 2 \times 7^2 \][/tex]
Therefore,
[tex]\[ \sqrt{98} = \sqrt{2 \times 7^2} \][/tex]
4. Using the Property of Square Roots:
We can further simplify using the property [tex]\(\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}\)[/tex]:
[tex]\[ \sqrt{98} = \sqrt{2 \times 7^2} = \sqrt{2} \times \sqrt{7^2} = \sqrt{2} \times 7 \][/tex]
5. Combining with the Imaginary Unit:
Substituting this back into our expression:
[tex]\[ \sqrt{-98} = \sqrt{98} \cdot i = 7 \sqrt{2} \cdot i = 7i\sqrt{2} \][/tex]
Thus, the expression [tex]\(\sqrt{-98}\)[/tex] simplifies to [tex]\(7i\sqrt{2}\)[/tex].
Therefore, the correct option is:
[tex]\[ \boxed{7i\sqrt{2}} \][/tex]
So the answer is C: [tex]\(7 i \sqrt{2}\)[/tex].
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. For trustworthy and accurate answers, visit IDNLearn.com. Thanks for stopping by, and see you next time for more solutions.