Discover the best answers to your questions with the help of IDNLearn.com. Ask your questions and receive detailed and reliable answers from our experienced and knowledgeable community members.

Find [tex]$7 \frac{1}{3} \div 2 \frac{1}{5}$[/tex]. Simplify the answer and write as a mixed number.

A. [tex]\frac{110}{33}[/tex]

B. [tex]1 \frac{2}{3}[/tex]

C. [tex]16 \frac{2}{15}[/tex]

D. [tex]3 \frac{1}{3}[/tex]


Sagot :

To find [tex]\( 7 \frac{1}{3} \div 2 \frac{1}{5} \)[/tex] and simplify the answer, follow these steps:

### Step 1: Convert the Mixed Numbers to Improper Fractions
First, convert the mixed numbers into improper fractions.
- For [tex]\( 7 \frac{1}{3} \: \[ 7 \frac{1}{3} = 7 + \frac{1}{3} = \frac{7 \times 3 + 1}{3} = \frac{22}{3} \] - For \( 2 \frac{1}{5} \: \[ 2 \frac{1}{5} = 2 + \frac{1}{5} = \frac{2 \times 5 + 1}{5} = \frac{11}{5} \] ### Step 2: Divide the Fractions To divide fractions, multiply by the reciprocal of the divisor. So, we calculate \(\frac{22}{3} \div \frac{11}{5}\)[/tex]:
[tex]\[ \frac{22}{3} \div \frac{11}{5} = \frac{22}{3} \times \frac{5}{11} \][/tex]

### Step 3: Perform the Multiplication
Multiply the numerators and the denominators:
[tex]\[ \frac{22 \times 5}{3 \times 11} = \frac{110}{33} \][/tex]

### Step 4: Simplify the Fraction
Simplify [tex]\(\frac{110}{33}\)[/tex] by finding the greatest common divisor (GCD) of 110 and 33, which is 11.
[tex]\[ \frac{110 \div 11}{33 \div 11} = \frac{10}{3} \][/tex]

### Step 5: Convert the Improper Fraction to a Mixed Number
Convert [tex]\(\frac{10}{3}\)[/tex] to a mixed number by dividing the numerator by the denominator.
[tex]\[ 10 \div 3 = 3 \text{ remainder } 1 \][/tex]
So, [tex]\(\frac{10}{3}\)[/tex] is [tex]\(3\frac{1}{3}\)[/tex].

Thus, the answer to [tex]\( 7 \frac{1}{3} \div 2 \frac{1}{5} \)[/tex] is [tex]\(\boxed{3 \frac{1}{3}}\)[/tex].
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Find reliable answers at IDNLearn.com. Thanks for stopping by, and come back for more trustworthy solutions.